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3 years ago

PLEASE HELP!

Mathematics

1 answer:

kondaur [170]3 years ago

6 0

I need more info on this ? to answer.

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The baker pays $0.80 per pound for sugar and $1.25 per pound for butter. Write an expression that shows how much the baker will

alekssr [168]

X is sugar
y is butter
z is total money

$0.80x + $1.25y = z

the total money spent if the Baker bought 6 pounds of butter and 20 pounds of sugar would be $23.50.

5 0

4 years ago

Read 2 more answers

If you have 100 feet of fence, which measurements would give you the largest area?

ivolga24 [154]

Answer:

25x25x25x25 Perfect square!

Step-by-step explanation:

Perfect square will always give you the most surface area.

So in this case...

100/4=25ft each side.

Thanks for letting me help!!

3 0

4 years ago

Helppppppppppppppppppppp<br><br> its math lol

n200080 [17]

Step-by-step explanation:

d. 5x+3y=15 is the answer

coordinate 3,0 and 0,5

5•3 +(3•0)=15

5•0 +(3•5)=15

3 0

3 years ago

Need help solve for x

Alenkinab [10]

$30 dollars i thinks cause 40 minus 30 is ten

4 0

4 years ago

URGRENNTTT PLSS HELPP 50 POINTSS!!!!! Students were asked to simplify the expression cotangent theta plus tangent theta over cot

Naddika [18.5K]

The student that simplified the expression incorrectly is student 2

<h3>How to determine the incorrect result?</h3>

The steps are given as:

$\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)}$

Student 1:

Step 1: $\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}$
Step 2: $1 + \frac{\tan(\theta)}{\cot(\theta)}$
Step 3: 1 + tan²(Ф)
Step 4: sec²(Ф)

Student 2:

Step 1: $\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)}$
Step 2: $\frac{1 + \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}$
Step 3: sec²(Ф)/tan²(Ф)
Step 4: csc²(Ф)

As a general trigonometry rule;

$\frac{\cot(\theta) + \tan(\theta)}{\cot(\theta)} = \sec^2(\theta)$

This means that student 1 is correct, while student 2 is not

The first error in student 2's workings is in step 2, where we have:

$\frac{\cot(\theta)}{\cot(\theta)} + \frac{\tan(\theta)}{\cot(\theta)} = \frac{1 + \tan^2(\theta)}{\cot(\theta)/\tan(\theta)}$

The above expression is not justified and cannot be proved by any trigonometry rule

Since the step 2 is incorrect, the other steps cannot be used.

Hence, the student that simplified the expression incorrectly is student 2

Read more about trigonometric expressions at:

brainly.com/question/8120556

#SPJ1

5 0

2 years ago