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Lynna [10]
2 years ago
8

PLEASE HELP!

Mathematics
1 answer:
kondaur [170]2 years ago
6 0
I need more info on this ? to answer.
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Solve the equations 11(x+10)=132
VladimirAG [237]
11(x+10) = 132

Distributive property

11x + 110 = 132

Now isolate the variable. 

11x + 110 = 132
        -110     -110

132 - 110 = 22

11x = 22

11x/11 = 22/11
x= 2

Answer:  x = 2

4 0
3 years ago
Read 2 more answers
The heaviest dinosaur is estimated to have welghed 2.8 x 10^5 pounds. The average car weighs about 4 x 10^3 pounds.
34kurt

Answer:

  70

Step-by-step explanation:

Apparently, you want the ratio of the weights:

  (dino weight)/(car weight) = (2.8×10^5)/(4×10^3)

  = (2.8/4)×10^(5-3) = 0.7×10^2 = 0.7×100

  = 70

The heaviest dinosaur weighed about 70 times the weight of an average car.

_____

Your calculator can do arithmetic in scientific notation. So can any spreadsheet.

The applicable rule of exponents is ...

  (10^a)/(10^b) = 10^(a-b)

4 0
3 years ago
On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
2 years ago
Can the following question be considered a statistical question and why or why not?
FinnZ [79.3K]

It could. If you turn it into an experiment. Let's say you take 100 students from each grade, and you ask them if they exercise. And then you wanna create a graph. And find out out of those students how many of them exercise and how many of them do not. Then turn it into a percent.

I hope this helps. If you have any further questions on this or any other questions just ask. I am here to help you, as needed.

7 0
3 years ago
Read 2 more answers
1 of 4
Serhud [2]
7 Did occurred twice. So 7 is the mode.
4 0
2 years ago
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