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2 years ago

PLEASE HELP!

Mathematics

1 answer:

kondaur [170]2 years ago

6 0

I need more info on this ? to answer.

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"Find the value of x. Round to the nearest tenth. Refer to the attachment below. "

AlexFokin [52]

$Use\ \cos.\\\\\cos24^o=\dfrac{11}{x}\\\\\cos24^o\approx0.9135\\\\\dfrac{11}{x}\approx0.9135\ \ \ |cross\ multiply\\\\0.9135x\approx11\ \ \ \ |divide\ both\ sides\ by\ 0.9135\\\\x\approx12$

7 0

3 years ago

Solve the system of linear equations by substitution. 3x + y = -9 y=5x+7

11Alexandr11 [23.1K]

Answer:

The solution is x = -2, y = -3

Step-by-step explanation:

Let's start with the equation 3x + y = -9

Substitute the y for 5x+7 seen in the second equation

Now you have 3x + (5x+7) = -9

Lets solve:

Let's add the x's

Now we have 8x + 7 = -9

Substracy seven from each side

Now we have 8x = -16

Now let's divide 8 on each side

Now we have x = -2

Now lets plug in -2 to the second equation

The second equation is y = 5x+7

When we plug in -2 we get y=5(-2)+7

We multiply

We now have y = -10+7

Add

y = -3

The solution is x = -2, y = -3

8 0

2 years ago

What is the definition of mathematics?

Andrew [12]

the abstract science of number, quantity, and space.

4 0

2 years ago

Read 2 more answers

A student on a piano stool rotates freely with an angular speed of 2.85 rev/s . The student holds a 1.50 kg mass in each outstre

Vlad1618 [11]

Answer:r'=0.327 m

Step-by-step explanation:

Given

$N=2.85 rev/s$

angular velocity $\omega =2\pi N=17.90 rad/s$

mass of objects $m=1.5 kg$

distance of objects from stool $r_1=0.789 m$

Combined moment of inertia of stool and student $=5.53 kg.m^2$

Now student pull off his hands so as to increase its speed to 3.60 rev/s

$\omega _2=2\pi N_2$

$\omega _2=2\pi 3.6=22.62 rad/s$

Initial moment of inertia of two masses $I_0=2mr_^2$

$I_0=2\times 1.5\times (0.789)^2=1.867$

After Pulling off hands so that r' is the distance of masses from stool

$I_0'=2\times 1.5\times (r')^2$

Conserving angular momentum

$I_1\omega =I_2\omega _2$

$(5.53+1.867)\cdot 17.90=(5.53+I_o')\cdot 22.62$

$I_0'=1.397\times 0.791$

$I_0'=5.851$

$5.53+2\times 1.5\times (r')^2=5.851$

$2\times 1.5\times (r')^2=0.321$

$r'^2=0.107009$

$r'=0.327 m$

7 0

3 years ago

Of the 18 teachers in Shane's school,

grin007 [14]

9:7 is the answer yeah

5 0

3 years ago