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Mariulka [41]
2 years ago
8

A 5. 0-c charge is 10 m from a small test charge. what is the magnitude of the force experienced by a 1. 0 nc charge placed at t

he location of the test charge?
Physics
1 answer:
sveta [45]2 years ago
4 0

The magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.

To find the answer, we have to know more about the force experienced between two charges.

<h3>How to find the force experienced between two charges?</h3>
  • It is given that,

                Q_1=5C\\Q_2=1C\\r=10m.

  • We have to find the force experienced between two charges,

               F=\frac{kQ_1Q_2}{r^2}

where, k=8.99*10^9.

  • Thus, by substitution, the force will be,

          F=\frac{8.99*10^9*5*1}{10^2} =4.5*10^8N

Thus, we can conclude that, the magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.

Learn more about the force here:

brainly.com/question/4086258

#SPJ4

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This question is incomplete, the complete question is;

Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. The electric field strength 1.5 m from the center of the circle is 7 mV/m.

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Answer:

the magnetic field changing at the rate of 9.33 m T/s

Explanation:

Given the data in the question;

Electric field E = 7 mV/m

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Now, from Faraday law of induction;

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The average diameter of one tennis ball in a package of three is 6.8 cm. Which of the following is the combined volume of all th
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We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3

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Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:

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3*V = 3*164.5cm^3 = 493.7 cm^3

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