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Mariulka [41]
1 year ago
8

A 5. 0-c charge is 10 m from a small test charge. what is the magnitude of the force experienced by a 1. 0 nc charge placed at t

he location of the test charge?
Physics
1 answer:
sveta [45]1 year ago
4 0

The magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.

To find the answer, we have to know more about the force experienced between two charges.

<h3>How to find the force experienced between two charges?</h3>
  • It is given that,

                Q_1=5C\\Q_2=1C\\r=10m.

  • We have to find the force experienced between two charges,

               F=\frac{kQ_1Q_2}{r^2}

where, k=8.99*10^9.

  • Thus, by substitution, the force will be,

          F=\frac{8.99*10^9*5*1}{10^2} =4.5*10^8N

Thus, we can conclude that, the magnitude of the force experienced by a 1. 0 c charge placed at the location of the test charge is 4.5*10^8N.

Learn more about the force here:

brainly.com/question/4086258

#SPJ4

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Calculate the frequency of the red light emitted by a neon sign with a wavelength of 690 nm
Ne4ueva [31]

Answer:

4.35 \times 10^{14} Hz

Explanation:

The frequency of a light is inversely proportional to its wavelength. It is given by:

f = \frac{v}{\lambda}

The speed of the red light, v = 3.0 × 10⁸ m/s

The wavelength of the red light, λ = 690 nm = 690 ×10⁻⁹ m

f = \frac{3.0 \times 10^8 m/s}{690\times 10^{-9}m} = 4.35 \times 10^{14} Hz

Thus, the frequency of red light emitted by neon sign having wavelength 690 nm is 4.35 \times 10^{14} Hz

7 0
3 years ago
Read 2 more answers
The distance from the dwarf planet Pluto to the sun is 4.43 × 109 km at perihelion and 7.37 × 109 km at aphelion. Find the eccen
kaheart [24]

Answer:

0.249

Explanation:

Perihelion = 4.43 x 10^9 km

Aphelion = 7.37 x 10^9 km

Let e be the eccentricity and a be the length of semi major axis.

The relation between the semi major axis, perihelion and aphelion s given by

Semi major axis = half of sum of perihelion and aphelion

a = \frac{4.43+7.37}{2}\times10^{9}

a = 5.9 x 10^9 km

The relation between the perihelion, semi major axis and the eccentricity is given by

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4.43 x 10^9 = 5.9 x 10^9 (1 - e)

0.751 = 1 - e

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3 0
2 years ago
What is the mass of the object being measured?
ioda

Answer:

m = 375 [gram]

Explanation:

A triple Beam balance is an instrument very easy to use, since we only have to perform the arithmetic sum of each of the weights that are recorded in each beam

m = 300 + 70 + 5 = 375 [gram]

For a better understanding, the following image is attached, with values on each beam, which should be read.

The largest mass is in the indicator of 100 [gram], the second mass is in the indicator of 20 [gram] and the third is in the indicator of 5.8 [gram]. Thus the arithmetic sum corresponds to:

M= 100 + 20 + 5.8 = 125.8 [gram]

Note: it is important that when the instrument is in balance, the opposite end of the beam should indicate a position of zeros.

6 0
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