The magnitude of the current in wire 3 is (I₃)= 0.33A
<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>
To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,
I₁ + I₂ + I₃ = 0
Where we are given,
I₁ = current in wire 1
=0.40 A.
I₂ = current in wire 2
= -0.73 A.
We have to calculate the magnitude of the current in wire 3, I₃
Now we put the known values in above equation, we get,
I₁ + I₂ + I₃ = 0
Or, I₃ = -.(I₁ + I₂)
Or, I₃ = -.(0.40 - 0.73)
Or, I₃ = 0.33 A
From the above calculation, we can conclude that the current in wire 3 is I₃ = 0.33 A
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True. Electromagnetic energy does not require a medium.
Answer:
Constructive interference
Explanation:
- This is an example of a standing wave produced when two ends of a string are oscillated in the same plane. The displacement of of point on two ends oscillates vertically.
- We are given that two pulses move along the string each coming towards each other and meet at a common point ( P ).
- Each pulse have their own magnitude or displacement in the vertical plane. If the pulses are to meet at a common point at the same instant, then they interfere with each other constructively.
- Where constructive interference of two pulses is the addition of magnitudes of induvidual pulses and form a single puls of the constructed magnitude.
magnitude ( New pulse ) = magnitude (Pulse 1) + magnitude (Pulse 2)
