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sergij07 [2.7K]
3 years ago
7

The diagram below shows a box with

Chemistry
1 answer:
Delicious77 [7]3 years ago
5 0
The answer is: D the box will NOT move or change. Hope this helps!
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Members of a species can mate with each other and produce
Georgia [21]
Fertile offspring mate is a form of reproduction
6 0
2 years ago
Consider the reaction of ruthenium(III) iodide with carbon dioxide and silver. RuI3 (s) 5CO (g) 3Ag (s) Ru(CO)5 (s) 3AgI (s) Det
mixer [17]

Answer:

71.6 g of Ru(CO)₅ is the maximum mass that can be formed.

The limiting reactant is Ag

Explanation:

The reaction is:

RuI₃ (s) + 5CO (g) + 3Ag (s) → Ru(CO)₅ (s) + 3AgI (s)

Firstly we determine the moles of each reactant:

169 g . 1mol /481.77g = 0.351 moles of RuI₃

58g . 1mol /28g = 2.07 moles of CO

96.2g . 1mol/ 107.87g = 0.892 moles

Certainly, the excess reactant is CO, therefore, the limiting would be Ag or RuI₃.

3 moles of Ag react to 1 mol of RuI₃

Then 0.892 moles of Ag may react to (0.892 . 1) /3 = 0.297 moles

We have 0.351 moles of iodide and we need 0.297 moles, so this is an excess. In conclussion, Silver (Ag) is the limiting.

1 mol of RuI₃ react to 3 moles of Ag

Then, 0.351 moles of RuI₃ may react to (0.351 . 3) /1 = 1.053 moles

It's ok, because we do not have enough Ag. We only have 0.892 moles and we need 1.053.

5 moles of CO react to 3 moles of Ag

Then, 2.07 moles of CO may react to (2.07 . 3) /5 = 1.242 moles of Ag.

This calculate confirms the theory.

Now, we determine the maximum mass of Ru(CO)₅

3 moles of of Ag can produce 1 mol of Ru(CO)₅

Then 0.892 moles may produce (0.892 . 1) /3 = 0.297 moles

We convert moles to mass → 0.297 mol . 241.07g /mol = 71.6 g

8 0
3 years ago
What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin
beks73 [17]

Answer:

\boxed{\text{2 mol/L}}

Step-by-step explanation:

c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }

Data:

n = 5 mol

V = 2.5 L

Calculation:

c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}

The molar concentration of the solution is \boxed{\textbf{2 mol/L}}.

6 0
3 years ago
An electron in a hydrogen atom moves from level 1 to level 4. The electron then drops from level 4 to level 2. Which
-Dominant- [34]

Answer:

The energy absorbed in the first move is greater than the energy released in the second move

Explanation:

Electrons require (absorb) energy to move to a higher energy level when there is a large external heat source, the presence of an electric field or by colliding with other electrons

And the amount of energy absorbed by the electron is exactly equal to the change in the energy state between the initial energy level of the electron and the destination energy level

Therefore, given that the energy level of the electron at level 2 is higher than the energy level of the electron when at level 1, we have;

The difference in the energy level between level 4 and level 1 is greater than the difference in the energy level between level 4 and level 2 and more energy is absorbed and therefore, released when the electron moves from level 1 to level 4 than when the electron drops from level 4 to level 2.

The most likely result is that 'the energy absorbed in the first move is greater than the energy released in the second move'.

5 0
3 years ago
HELP ME ASAP PLEASE AND THANK YOU
mafiozo [28]
F I think since the one on the worst line is an E so I’m pretty sure it’s F :p
7 0
3 years ago
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