Answer:
112.625 mL
Explanation:
Applying,
ML = M'L'.................... Equation 1
Where M = Initial molarity or concentration of calcium chloride, L = initial volume of calcium chloride, M' = Final molarity of calcuim chloride, L' = Final volume of calcuim chloride.
make L the subeject of the equation
L = M'L'/M................ Equation 2
From the question,
Given: M = 1.60 mol/L, M' = 0.34 mol/L, L' = 530 mL
Substitute these values into equation 2
L = (0.34×530)/1.60
L = 112.625 mL
Trihydrate - basically 3 molecules of water. Unless you're referring to the molecule 3H2O used in measuring the total body water in the case it tritiated water.
Answer:
Specific heat of metal of the metal is 0.8394J/g°C
Explanation:
The heat the water gain is the same losing for the metal. The equation is:
m(Metal)*ΔT(Metal)*S(Metal) = m(Water)*ΔT(Water)*S(Water)
<em>Where m is mass: 66.0g water and 28.5g Metal</em>
<em>ΔT is change in temperature: (95.25°C-27.84°C) = 67.41°C for the metal and (27.84°C - 22.00°C) = 5.84°C for the water</em>
<em>And S is specific heat of water (4.184J/g°C) and the metal</em>
<em />
Replacing:
28.5g*67.41°C*S(Metal) = 66.0g*5.84°C*4.184J/g°C
S(Metal) = 0.8394J/g°C
<h3>Specific heat of metal of the metal is 0.8394J/g°C</h3>
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CO2
The symbol how you write
