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Eddi Din [679]
2 years ago
6

Inertia is the property that every material object has that causes objects to resist changes in its state of motion

Physics
2 answers:
krok68 [10]2 years ago
4 0

The statement "Inertia is the property that every material object has that causes objects to resist changes in its state of motion" is true

<u>Explanation:</u>

Inertia defines as the resistance produced by the body or an objects to vary in its states of motion, by an external force. An external agent cannot disturb a body, until it has more magnitude than its normal force. Normal force is nothing but due to the mass of the body, being in contact with the ground.

So, inertia is purely dependent on the mass of the body. The unit of inertia is ‘kg’. Inertia, the complete dependent of mass of a body, and also the main reason for the normal force, can stop a body from changing its state.

jonny [76]2 years ago
3 0
True :) good luck on your quiz
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An oscillator consists of a block attached to a spring (k = 427 N/m). At some time t, the position (measured from the system's e
White raven [17]

Answer:

a) 4.49Hz

b) 0.536kg

c) 2.57s

Explanation:

This problem can be solved by using the equation for he position and velocity of an object in a mass-string system:

x=Acos(\omega t)\\\\v=-\omega Asin(\omega t)\\\\a=-\omega^2Acos(\omega t)

for some time t you have:

x=0.134m

v=-12.1m/s

a=-107m/s^2

If you divide the first equation and the third equation, you can calculate w:

\frac{x}{a}=\frac{Acos(\omega t)}{-\omega^2 Acos(\omega t)}\\\\\omega=\sqrt{-\frac{a}{x}}=\sqrt{-\frac{-107m/s^2}{0.134m}}=28.25\frac{rad}{s}

with this value you can compute the frequency:

a)

f=\frac{\omega}{2\pi}=\frac{28.25rad/s}{2\pi}=4.49Hz

b)

the mass of the block is given by the formula:

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}\\\\m=\frac{k}{4\pi^2f^2}=\frac{427N/m}{(4\pi^2)(4.49Hz)^2}=0.536kg

c) to find the amplitude of the motion you need to know the time t. This can computed by dividing the equation for v with the equation for x and taking the arctan:

\frac{v}{x}=-\omega tan(\omega t)\\\\t=\frac{1}{\omega}arctan(-\frac{v}{x\omega })=\frac{1}{28.25rad/s}arctan(-\frac{-12.1m/s}{(0.134m)(28.25rad/s)})=2.57s

Finally, the amplitude is:

x=Acos(\omega t)\\\\A=\frac{0.134m}{cos(28.25rad/s*2.57s )}=0.45m

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