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Gnesinka [82]
3 years ago
5

Physicists often use a different unit of energy, the electron volt, when dealing with energies at the atomic level. One electron

volt, abbreviated eV, is defined as the amount of kinetic energy gained by an electron upon accelerating through a 1.0 V potential difference.
a) what is 1.0 electron volt in joules?

b) what is the speed of a proton with 5000 eV of kinetic energy?
Physics
1 answer:
Alex Ar [27]3 years ago
3 0

Answer:

a)  E = 1.06 10⁻¹⁹ J,     b)   v = 9.78 10⁵ m / s

Explanation:

The physical magnitudes can be given in several units, but in general all must be reduced to the same system in a given exercise, the most used system is the international (SI)

           1 eV =q V=  1.6 10⁻¹⁹ J

let's reduce the quantities requested

a) E = 1.0 eV to Joule

           E = 1.0 eV (1.6 10⁻¹⁹ J / 1 eV)

           E = 1.06 10⁻¹⁹ J

b) the kinetic energy is given by

           K = ½ m v²

           v = \sqrt{\frac{2K}{m} }

the mass of the proton is

          m = 1,673 10⁻²⁷ kg

let's reduce the energy to the SI system

           E = 5000 ev (1.6 10-19 J / 1 eV) = 8000 10⁻¹⁹ J

let's calculate

           v = \sqrt{ \frac{2 \ 8000 \ 10^{-19}}{1.673 \ 10^{-27} }  }

           v = \sqrt{ 95.637 \  10^{10} }

           v = 9.78 10⁵ m / s

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4 years ago
A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotat
slava [35]

Answer: the angular frequency is 2.31 rad/s

Explanation:

The data we have is:

Radial acceleration A = 27.9 m/s^2

Beam length r = 5.21m

The radial acceleration is equal to the velocity square divided the radius of the circle (the lenght of the beam in this case)

And we can write the velocity as:

v = w*r where r is the radius of the circle, and w is the angular frequency.

w = 2pi*f

where f is the "normal" frequency.

So we have:

A = (v^2)/r = (r*w)^2/r = r*w^2

We can replace the values and find w.

27.9m/s^2 = 5.21m*w^2

√(27.9/5.21) = w = 2.31 rad/s

8 0
3 years ago
How is energy involved in the formation of a covalent bond?
frez [133]

The energy is involved in ionization, electron affinity etc

The following are the conditions that favor the creation of covalent bonds since they are generated by the mutual sharing of electrons:

  • Electron affinity, first. If both atoms have a strong electron affinity, a covalent link is often preferred between them.
  • The energy of ionization. The ionization energy of the two atoms participating in the bonding process should be high.
  • Atomic Dimension. The atoms that form covalent bonds should have lower atomic sizes. Stronger covalent bonds are created when atoms have smaller atomic radii.
  • Electronegativity. Both atoms' electronegativities ought to be high. The two atoms' electronegativities should differ as little as possible.
  • In order to establish covalent bonds, the atoms' high ionization energy is involved.

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5 0
1 year ago
A flight distance from philadelphia to cancun is 1469 miles.the estimated flight time is 3.25 hours.What is the avarage speeede
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Answer:

1469 miles /3.25 hours = 452 miles per hours

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4 0
3 years ago
The enthalpy of fusion of mercury is 2.292 kJ mol-1 at its normal freezing point of 234.3 K; the change in molar volume on melti
aev [14]

Answer:

T_2= 234.37 K

Explanation:

According to Claperyon, we know that

P_2-P_1= \frac{\Delta H_{fus}}{\Delta V}\times\frac{T_1}{T_2}

P_1= Atmospheric pressure 760 mm Hg

P_2 = pressure at the bottom of the column

= 10×10^3 mm of Hg+ 760 mm of Hg

= 10760 mm of Hg

now,

P_2-P_1= 10760-760= 10^4 mm

P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm

the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol

use the above equation to calculate ΔT as follows

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therefore, T_2= 234.37 K

6 0
3 years ago
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