Answer:
September 9 and 24 represent spring tides due to the added gravitational pull of the Sun.
Explanation:
Just trust me
Answer: the angular frequency is 2.31 rad/s
Explanation:
The data we have is:
Radial acceleration A = 27.9 m/s^2
Beam length r = 5.21m
The radial acceleration is equal to the velocity square divided the radius of the circle (the lenght of the beam in this case)
And we can write the velocity as:
v = w*r where r is the radius of the circle, and w is the angular frequency.
w = 2pi*f
where f is the "normal" frequency.
So we have:
A = (v^2)/r = (r*w)^2/r = r*w^2
We can replace the values and find w.
27.9m/s^2 = 5.21m*w^2
√(27.9/5.21) = w = 2.31 rad/s
The energy is involved in ionization, electron affinity etc
The following are the conditions that favor the creation of covalent bonds since they are generated by the mutual sharing of electrons:
- Electron affinity, first. If both atoms have a strong electron affinity, a covalent link is often preferred between them.
- The energy of ionization. The ionization energy of the two atoms participating in the bonding process should be high.
- Atomic Dimension. The atoms that form covalent bonds should have lower atomic sizes. Stronger covalent bonds are created when atoms have smaller atomic radii.
- Electronegativity. Both atoms' electronegativities ought to be high. The two atoms' electronegativities should differ as little as possible.
- In order to establish covalent bonds, the atoms' high ionization energy is involved.
To learn more about covalent bond visit:
brainly.com/question/19382448
#SPJ9
Answer:
1469 miles /3.25 hours = 452 miles per hours
Explanation:
divide distance by the time it takes to get there
Answer:
T_2= 234.37 K
Explanation:
According to Claperyon, we know that

P_1= Atmospheric pressure 760 mm Hg
P_2 = pressure at the bottom of the column
= 10×10^3 mm of Hg+ 760 mm of Hg
= 10760 mm of Hg
now,
P_2-P_1= 10760-760= 10^4 mm
P_2-P_1 ( in pascals) = 10^4× 133.322= 1333220 mm
the enthalpy of fusion (ΔH-fus) of mercury is 2.292 KJ/mol
use the above equation to calculate ΔT as follows

therefore, T_2= 234.37 K