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2 years ago

10

Can someone please give me the answers to this? ... please ...

1 answer:

vodka [1.7K]2 years ago

8 0

Answer:

tell me if im wrong

Explanation:

ok and thaks sa points

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I need help immediately and thank you of if you answer the question

Svetach [21]

Answer:

c. Position C

Explanation:

As the magnetic force is the strongest at the end of the poles and it decreases when it comes to its centre.

5 0

2 years ago

A uniformly charged sphere has a potential on its surface of 450 V. At a radial distance of 8.1 m from this surface, the potenti

igomit [66]

Answer:

The radius of the sphere is 4.05 m

Explanation:

Given;

potential at surface, $V_s$ = 450 V

potential at radial distance, $V_r$ = 150

radial distance, l = 8.1 m

Apply Coulomb's law of electrostatic force;

$V = \frac{KQ}{r} \\\\V_s = \frac{KQ}{r} \\\\V_r = \frac{KQ}{r+ l}$

$450 = \frac{KQ}{r} ------equation (i)\\\\150 = \frac{KQ}{r+8.1} ------equation (ii)\\\\divide \ equation (i)\ by \ equation \ (ii)\\\\\frac{450}{150} = (\frac{KQ}{r} )*(\frac{r+8.1}{KQ} )\\\\3 = \frac{r+8.1}{r} \\\\3r = r + 8.1\\\\2r = 8.1\\\\r = \frac{8.1}{2} \\\\r = 4.05 \ m$

Therefore, the radius of the sphere is 4.05 m

4 0

2 years ago

Many compounds of living things, such as carbon dioxide, are formed by which kind of bond?

Anuta_ua [19.1K]

Answer:

im sorry i dont know

Explanation:

8 0

3 years ago

Read 2 more answers

A rock at rest falls off a tall cliff and hits the valley below after 3.5s. What is the rocks velocity as it hits the ground

pogonyaev

T = 3.5 secs

Velocity (v) = g * t = 10 m/s^2 * 3.5 sec = 35 m/s

7 0

3 years ago

Read 2 more answers

(a) What is the minimum width of a single slit (in multiples of λ ) that will produce a first minimum for a wavelength λ ? (b) W

Kitty [74]

Answer:

The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

Explanation:

Given that,

Wavelength = λ

For D to be small,

We need to calculate the minimum width

Using formula of minimum width

$D\sin\theta=n\lambda$

$D=\dfrac{n\lambda}{\sin\theta}$

Where, D = width of slit

$\lambda$ = wavelength

Put the value into the formula

$D=\dfrac{n\lambda}{\sin\theta}$

Here, $\sin\theta$ should be maximum.

So. maximum value of $\sin\theta$ is 1

Put the value into the formula

$D=\dfrac{1\times\lambda}{1}$

$D=\lambda$

(b). If the minimum number is 50

Then, the width is

$D=\dfrac{50\times\lambda}{1}$

$D=50\lambda$

(c). If the minimum number is 1000

Then, the width is

$D=\dfrac{1000\times\lambda}{1}$

$D=1000\lambda$

Hence, The minimum value of width for first minima is λ

The minimum value of width for 50 minima is 50λ

The minimum value of width for 1000 minima is 1000λ

4 0

3 years ago