Answer:
a = 85.3×10⁶ m/s²
Explanation:
Please see the attachment below.
Answer:
The speed of cart B is 11.21 m/s.
Explanation:
Given that,
Speed of cart A = 9.25 m/s
Speed of cart B = 7.15 m/s
Mass of cart A = 72.0 kg
Mass of cart B = 55.0 kg
Speed of card A after collision = 6.15 m/s
We need to calculate the speed of cart B
Using conservation of momentum

Put the value into the formula



Hence, The speed of cart B is 11.21 m/s.
Answer:
D-it's never acceptable to ignore rules and etiquette
Explanation:
Answer:
Approximately
. (Assuming that
, and that the tabletop is level.)
Explanation:
Weight of the book:
.
If the tabletop is level, the normal force on the book will be equal (in magnitude) to weight of the book. Hence,
.
As a side note, the
and
on this book are not equal- these two forces are equal in size but point in the opposite directions.
When the book is moving, the friction
on it will be equal to
, the coefficient of kinetic friction, times
, the normal force that's acting on it.
That is:
.
Friction acts in the opposite direction of the object's motion. The friction here should act in the opposite direction of that
applied force. The net force on the book shall be:
.
Apply Newton's Second Law to find the acceleration of this book:
.