density of the object = 0.53 g/mL
Explanation:
First we need to find the volume of the object which is equal to the rise of the water in the graduated cylinder:
volume = 31.7 - 25.1 = 6.6 mL
Now we calculate the density of the object using the following formula:
density = mass / volume
density = 3.5 g / 6.6 mL
density = 0.53 g/mL
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Answer:
Bottle 2 shows the vinegar has a molarity of 2M acetic acid
Explanation:
2M of acetic acid has higher concentration of acetic acid as compared to other vinegar. In 2M of acetic acid is equals to 120 gram of acetic acid in 500 ml of water which is quiet higher than other concentration of acetic acid in vinegar which is 4%. So Mr. Holmes has to use 2M of acetic acid which will produced high intense eruption in the volcano and win the national science fair contest.
Death rate has been caused by mutliple things in soceity, 254,867 by abortion heart disease 143,385.
The formal charges of all nonhydrogen atoms are -1.
Solution:-
<u>O 7-4 = 3 O Double bond on one H 5-4 = 1</u>
O-Cl-O 6-7 = -1x4 = -4 N 5-4=1 H-N-H 1-1=0
O 3-4= -1 O O 6-7 = -1(2)=-2 H 1-0=+1
<u>6-6 = 0 1-2 = -1</u>
It will percentage its last valence electron thru a single bond to the terminal oxygen atom. This is in agreement with carbon and hydrogen atoms that each need to form 4 and 1 covalent bonds respectively. because the terminal oxygen atom best has a single covalent bond, it'll have a proper rate of -1.
According to the lewis structure of SO2, The critical atom is sulfur and it is bonded with 2 oxygen atoms thru a double bond. each oxygen atom acquires 2 lone pairs of electrons and the primary sulfur atom has 1 lone pair of electrons.
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Answer:
Yes.
Explanation:
It should be noted that the meaning of molarity is the ratio of moles of solute per liter of solution.
It should be understood that when determining or finding the molarity of an unknown compound ,the process should be performed or carried out at least 3 times. This is done to remove any form of doubt.
The first calculated value for the concentration of the compound will be regarded as rough value, while the second and the third will be regarded as the first and second values respectively.
In this case, the third value for the concentration of HCl will be calculated to for confirmation of other value, that is to be finally sure of its concentration.
