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fgiga [73]
3 years ago
7

Find the distance to the nearest tenth

Mathematics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

d=11.2

Step-by-step explanation:

d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2} \\ }

d=\sqrt{(6-(-4)^{2}+(-3-2)^{2}  }

d=\sqrt{10^{2}+5^{2}  }

d=\sqrt{100+25}

d=\sqrt{125}

d=11.18

d=11.2

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