Question

Find the distance to the nearest tenth

Answer 1

Answer:

d=11.2

Step-by-step explanation:

$d=\sqrt{(x2-x1)^{2}+(y2-y1)^{2} \\ }$

$d=\sqrt{(6-(-4)^{2}+(-3-2)^{2} }$

$d=\sqrt{10^{2}+5^{2} }$

$d=\sqrt{100+25}$

$d=\sqrt{125}$

$d=11.18$

$d=11.2$