Answer: mole fraction of methanol = 0.590
mole fraction of ethanol = 0.410
Explanation:
We are given:
Equal masses of methanol
and ethanol
are mixed.
let the mass be x g.
Calculating the moles of methanol in the solution, by using the equation:

Calculating the moles of ethanol in the solution, by using the equation:

To calculate the mole fraction of methanol, we use the equation:


To calculate the mole fraction of ethanol, we use the equation:


Thus mole fraction of methanol is 0.590 and mole fraction of ethanol 0.410 in three significant figures.
Answer:
Explanation:
The acidity of a solution is measured by its pH, which is the logarithm of the inverse of the molar concentration of hydronium (H₃O⁺) ions:
- pH = log 1 / [H₃O⁺] = - log [H₃O⁺]
When you know the pH value you can find hydronium concentration using the antilogaritm function:
![pH=-log[H_3O^{+}]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-2.50}\\ \\ {[H_3O^+]}=0.0032](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%7B%2B%7D%5D%5C%5C%20%5C%5C%20%7B%5BH_3O%5E%2B%5D%7D%3D10%5E%7B-pH%7D%5C%5C%20%5C%5C%20%7B%5BH_3O%5E%2B%5D%7D%3D10%5E%7B-2.50%7D%5C%5C%20%5C%5C%20%7B%5BH_3O%5E%2B%5D%7D%3D0.0032)
The unit of molar concentration is M.
To prove your answer you can take the logarithm of 0.0316:
Answer:
C₁₂H₂₂O₁₁ and CH₃OH
Explanation:
Sucrose and methyl alcohol are nonelectrolytes. They do not ionize or conduct a current in aqueous solution.
HC₂H₃O₂ is a weak electrolyte. It produces only a few ions and is a poor conductor of electricity in aqueous solution.
HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O₂⁻
H₂SO₄ is a strong electrolyte. Its first ionization is complete, so it is a good conductor of electricity in aqueous solution.
H₂SO₄ + H₂O ⟶ H₃O⁺ + HSO₄⁻
Answer:
Neutralization reactions
Explanation:
A neutralization reaction is a reaction between an acid and a base. Products of this type of reaction is water and a salt. The pH of the salt product would depend on how strong or weak the base and acid would be when they react with each other. Although the characteristics of bases and acids are practically polar opposites, when combined, they cancel each other our producing a neutralized product.