9514 1404 393
Answer:
$7.50
Step-by-step explanation:
Rounded to the nearest $10, the $49.35 bill becomes $50.
We can find 10% of that amount by moving the decimal point to the left. 10% of $50 is $5.00.
Then 5% of $50 is half of 10%, so is $5/2 = $2.50.
The estimated tip of 15% is the sum of 10% and 5% of the bill, so is ...
15%($50) = 10%($50) +5%($50) = $5.00 +2.50 = $7.50
The estimated 15% tip is $7.50.
The sum of two numbers a and b decreased by their product is (a+b)-ab
Step-by-step explanation:
Given the two numbers as a and b
Sum of these two numbers is a+b
The product of the two numbers is a*b, ab
The sum of the two numbers decreased by their product will be;
(a+b)-ab
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Keywords : sum of two numbers, product
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Given :
Cost of single bottle, C = $1.69 .
Cost of 4 bottles, B = $5 .
You bought one bottle last week for $1.69 and one bottle this week at the 4 for $5 price.
To Find :
Did you pay more or less for the bottle this week at 4 for $5? How much more or less?
Solution :
Effective price per bottle if we purchase 4 is, E = 5/4 = $1.25 .
Regular price, R = $1.69 .
Change in price, C = $( 1.69 - 1.25 ) = $0.44 .
Therefore, we are paying $0.44 less than the actual price.
Hence, this is the required solution.
<h3>Answer:</h3>
(x, y) ≈ (1.49021612010, 1.22074408461)
<h3>Explanation:</h3>
This is best solved graphically or by some other machine method. The approximate solution (x=1.49, y=1.221) can be iterated by any of several approaches to refine the values to the ones given above. The values above were obtained using Newton's method iteration.
_____
Setting the y-values equal and squaring both sides of the equation gives ...
... √x = x² -1
... x = (x² -1)² = x⁴ -2x² +1 . . . . . square both sides
... x⁴ -2x² -x +1 = 0 . . . . . polynomial equation in standard form.
By Descarte's rule of signs, we know there are two positive real roots to this equation. From the graph, we know the other two roots are complex. The second positive real root is extraneous, corresponding to the negative branch of the square root function.