Answer:
12.15, 2.23
Explanation:
Using the dilution formula
C₁V₁ = C₂ V₂
where C₁ = 1.46 M
V₁ = 1.48 ml = 0.00148 L
C₂ = unknown
V₂ = 150 ml + 1.48ml = 151.48 ml = 0.15148L
1.46 M × 0.00148 L = C₂×0.15148L
C₂ = 0.0143 M
pOH = - log ( OH⁻) = - log ( 0.0143) = 1.85
pH + pOH = 14
pH = 14 - 1.85 = 12.15
b) using the same formula
C₁V₁ = C₂ V₂
C₁ = 0.99 M
V₁ = 1.49 ml = 0.00149 L
C₂ = unknown
V₂ = 250 ml + 1.49 ml = 251.49 ml = 0.25149 L
0.99 M × 0.00149 L = C₂ × 0.25149 L
C₂ = 0.00587
pH = - log ( H⁺) = - ( -2.23) = 2.23
The new volume of the gas is calculated using the Boyles law formula
that is P1V1=P2V2
P1=80 kpa
V1= 500 L
P2=400Kpa
V2=?
by making V2 the subject of the formula V2 =P1V1/P2
=(500 L x80 KPa)/400 KPa = 100 L is the new volume of the gas
There are materials embedded in rocks forming it shape and properties
The entropy of the given reactions increases (S° > 0):
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
<h3>What is entropy?</h3>
Entropy measure how disordered a system is. It a measure of how dispersed or random the total energy of a system is. The symbol for entropy is S.
A system in which entropy increases is one in which S° > 0.
The entropy of a system decreases when S° < 0.
Entropy of a system increases (S° > 0) if any change results in an increase in temperature, increase in number of molecules, or an increase in volume.
Considering the given systems, the entropy changes is as follows:
- 2C2H6(g) + 7O2(g) ----> 4CO2(g) + 6H2O(g) ---> S° > 0.
- 2CO2(g) + N2(g) ---->2CO(g) + 2NO(g) --> no change
- 2N2(g) + O2(g) -----> 2N2O(g) ---> decreases
- S (s,rhombic) + 2CO(g) ----> SO2(g) + 2C (s,graphite) ---> no change
- NH4Cl(s) ----> NH3(g) + HCl(g) ---> S° > 0.
In conclusion, an increase in volume and moles of substances results in entropy increase.
Learn more about entropy at: brainly.com/question/26691503
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