Can y’all Please help !!!!

All the following steps need to be followed when naming alkanes, except

goldfiish [28.3K]

A.

Begin numbering at the end closest to the first branch, not the farthest.

6 0

4 years ago

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Consider the reaction 4HCl(g) + O2(g)2H2O(g) + 2Cl2(g) Using standard thermodynamic data at 298K, calculate the entropy change f

Ulleksa [173]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$4HCl(g)+O_2(g)\rightarrow 2H_2O(g)+2Cl_2(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cl_2(g))})+(2\times \Delta S^o_{(H_2O(g))})]-[(4\times \Delta S^o_{(HCl(g))})+(1\times \Delta S^o_{(O_2(g))})]$

We are given:

$\Delta S^o_{(O_2(g))}=205.14J/K.mol\\\Delta So_{(HCl(g))}=186.91J/K.mol\\\Delta S^o_{(Cl_2(g))}=223.07J/K.mol\\\Delta S^o_{(H_2O(g))}=188.82J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (223.07))+(2\times (188.82))]-[(4\times (186.91))+(1\times (205.14))]\\\\\Delta S^o_{rxn}=-129J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(-129) J/K = 129 J/K

We are given:

Moles of HCl gas reacted = 2.27 moles

By Stoichiometry of the reaction:

When 4 mole of HCl gas is reacted, the entropy change of the surrounding will be 129 J/K

So, when 2.27 moles of HCl gas is reacted, the entropy change of the surrounding will be = $\frac{129}{4}\times 2.27=73.21J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of HCl gas is reacted is 73.21 J/K

3 0

3 years ago

The cubic centimeter, which is often abbreviated as cc or cm3, is a metric unit for

serg [7]

Answer:

Volume

Explanation:

Cubic centimeters are used to measure the space an object takes up, or its volume.

7 0

3 years ago

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How many particles would be found in a 12.7 g sample of ammonium carbonate? Show workkk

Sophie [7]

Answer:

7.8286×10²¹ particles

Explanation:

give me brainlist please

3 0

3 years ago

Helium (He), oxygen (O), carbon (C) fluorine (F), and chlorine (Cl) are all nonmetals. Using the periodic table, which pair of n

Delicious77 [7]

Answer:

fluorine (F), and chlorine (Cl) because they are both halogens and belong to the same group in the periodic table

Explanation:

The pair of non - metals in the elements given that will have similar properties are chlorine and Fluorine.

This is because they both are elements commonly known by the group name Halogens which belong to group 7A.

Properties of halogens include;

- They are very reactive, have single covalent bonds and readily form other compounds.

- In the gaseous state, they will form diatomic covalent molecules.

Whereas, helium is a group 8 element, oxygen is a group 6 element while carbon is a group 4 element.

7 0

3 years ago