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3 years ago

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Can y’all Please help !!!!

1 answer:

ycow [4]3 years ago

4 0

Answer:

yes

Explanation:

<em>pp popo</em>

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How do we use properties of matter in our every day lives

bearhunter [10]

For example, water. In its liquid state we drink it , in its solid state (ice ) we use it to make our drinks colder or t numbs pain when wrapped in cloth and it’s gas state ( water vapour) we steam vegetables. In conclusion many different properties of matter are used for various purposes

6 0

3 years ago

A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /

Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

$t_{1}$ = 25 °C

$t_{2}$ = 36,4 °C

Q = 325 J

The formula is: Q = c * m * ( $t_{2} - t_{1}$ )

m = $\frac{Q}{c * (t_{2} - t_{1} )}$

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0

3 years ago

Which of the following lists the correct symbol for the ion that tin forms when it loses 2 electrons, the correct classification

ser-zykov [4K]

Answer:

$\huge\boxed{\sf Option \ A}$

Explanation:

The symbol for TIN is Sn.

When Sn loses 2 electrons, it gets a double positive charge ( +2 ) and becomes $\sf Sn ^{+2}$ .

It becomes a cation.

The name of Ion is Tin ( II ) Ion.

$\rule[225]{225}{2}$

Hope this helped!

<h3>~AH1807</h3>

6 0

3 years ago

Read 2 more answers

Land breezes near bodies of water occur because

Aleksandr [31]

B) land cools off much faster than water (creating a air region of high density above land and lower density above sea)

6 0

3 years ago

calculate how much acid (acetic acid) and how much conjugate base (sodium acetate) must be used to make 500ml of a 0.8m acetate

kirza4 [7]

For the desired pH of 5.76, 0.365 mol of acetate and 0.035 mol of acid are to be added

let the concentration of acetate be x

then the concentration of acid will be (0.8 - x)

pKa of acetate buffer = 4.76

pH = pKa + log([acetate]/[acid])

⇒4.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 0

⇒x/(0.8-x) = 1

⇒x = 0.4

Therefore

[acetate] = x = 0.4

[acid] = 0.8-x =0.4 M

number of mol = concentration *(volume in mL)

number of mol of acetate = 0.4*0.5

= 0.20 mol

number of mol acid = 0.4*0.5

= 0.20 mol

when desired pH = 5.76

pH = pKa + log([acetate]/[acid])

⇒5.76 = 4.76 + log(x/(0.8-x))

⇒log(x/(0.8-x)) = 1

⇒x/(0.8-x) = 10

⇒x = 8 - 10x

⇒x = 8/11

⇒x= 0.73

[acetate] = x= 0.73

[acid] = 0.8-x = 0.07 M

number of mol = concentration * (volume in mL)

number of mol acetate to be added = 0.73*0.5 = 0.365 mol

number of mol acid to be added = 0.07*0.5 = 0.035 mol

Problem based on acetic acid required to maintain a certain pH

brainly.com/question/9240031

#SPJ4

4 0

1 year ago