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postnew [5]
4 years ago
14

GUYS PLS HELP

Chemistry
1 answer:
Alchen [17]4 years ago
7 0
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Which is a characteristic of mixtures?
d1i1m1o1n [39]

Answer: They can be separated by physical processes.

Explanation: A mixture is made up of two or more substances that are not chemically combined and can be easily separated into its constituents by physical methods.

8 0
3 years ago
When the equation N=O/P is solved for P correctly, the equation should read:
zheka24 [161]

Given the equation N=O/P, solve for P by multiplying the left and right by P/N:

N * P/N = O/P * P/N

P = O/N


3 0
4 years ago
Read 2 more answers
02. Using Tables 1 to 3, what pattern do you observe in terms of the phase and number of carbon atoms of the alkanes, alkenes, a
BabaBlast [244]

Hey there mate ;), Im Benjemin and lets solve your question.

★ (Alkanes) : forms single bonds between carbon atoms.

The first four elements are gases and others are liquid in state.

★(Alkenes) : forms double bonds between carbon atoms.

The first three alkenes are gases and rest are liquid.

★ (Alkynes) : forms triple bonds between carbon atoms.

First three are gases and the last one is liquid.

According to boiling point :

The larger structure of the hydrocarbons, the higher the boiling points they have.

In the 3 tables, we can see that the boiling point increases.

5 0
3 years ago
Look closely at the valence electrons in all eight columns of your table from part C. Which element's location does not
maw [93]

Answer: helium(He)

Explanation: Helium has only 2 electrons in the outermost energy level, but all of the other elements in its column have eight.

5 0
3 years ago
What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL

3 0
4 years ago
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