GUYS PLS HELP

Calculate the speed of a marble that rolls 9 cm in 4 seconds

cupoosta [38]

Answer:

2.25

Explanation:

9/4

6 0

3 years ago

Which of these is a unique property of bases?

tatuchka [14]

Answer:

A. Feels slippery

Explanation:

Bases are the only types of compounds that have a slippery feel.

B is wrong. Most bases do not contain carbon, but organic compounds always do.

C is wrong. Aqueous solutions of bases conduct electricity, but so do aqueous solutions of salts.

D is wrong. Most bases have a bitter taste. Acids have a sour taste.

7 0

3 years ago

Sediments are almost always deposited in flat layers. Does it appear that forces in the Earth affected the rock layers in this r

laiz [17]

I think so but what region do you live in

4 0

2 years ago

Which statement best describes an igneous intrusion?

Andrew [12]

D. Magma is injected into surrounding rock forming an igneous intrusion.

Igneous intrusion forms when magma from under the surface of the earth is slowly pushed up to occupy spaces or cracks found among rocks and cools down and solidifies before it reaches the surface of the earth.

4 0

3 years ago

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

a

$\Delta H^o _{rxn} = -2568.9 \ kJ$

b

$H = 350 JK^{-1}$

c

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$