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3 years ago

How would you get your friend to change his/her mind from using PED's?

Physics

1 answer:

kvasek [131]3 years ago

6 0

Answer:

Watch funny videos and start eating a lot of candy

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A very long, straight solenoid with a cross-sectional area of 2.39cm2 is wound with 85.7 turns of wire per centimeter. Starting

babymother [125]

Answer: The magnitude of the emf induced in the secondary winding is 1.85×10^-5 V

Explanation: Please see the attachments below

4 0

3 years ago

In a crash test the strapped-in, 75-kg dummy moves a distance of 0.80 m when the test car is slammed straight into a wall at 11.

Brums [2.3K]

Explanation:

It is given that,

Mass of the dummy, m = 75 kg

Distance, d = 0.8 m

Initial speed of the dummy, u = 0

Final speed of the dummy, v = 11.2 m/s

Firstly finding the acceleration of the test car. Using third equation of motion to find it as :

$v^2-u^2=2ad$

$v^2=2ad$

$a=\dfrac{v^2}{2d}$

$a=\dfrac{(11.2)^2}{2\times 0.8}$

$a=78.4\ m/s^2$

Let F is the average force. It is given by the product of mass and acceleration. It is given by :

$F=ma$

$F=75\times 78.4$

F = 5880 N

Taking ratios,

$\dfrac{F}{W}=\dfrac{ma}{mg}$

$\dfrac{F}{W}=\dfrac{a}{g}$

$\dfrac{F}{W}=\dfrac{78.4}{9.8}$

$\dfrac{F}{W}=8$

$F=8W$

The average force acting on the dummy during the collision is 8 times of his weight. Hence, this is the required solution.

3 0

4 years ago

A long solenoid, of radius a, is driven by an alternating current, so that the field inside is sinusoidal: B(t) B cos(ot)ż. A ci

Scrat [10]

Answer:

The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

Explanation:

Given that,

Magnetic field $B(t)=B\cos(\omega t)\ z$

Radius $r =\dfrac{a}{2}$

Resistance =R

We need to calculate the area of the loop

Using formula of area

$A = \pi r^2$

Put the value of r in to the formula

$A =\pi\times(\dfrac{a}{2})^2$

$A=\dfrac{\pi a^2}{4}$

We need to calculate the flux

Using formula of flux

$\phi=BA$

$\phi=B\cos(\omega t)\dfrac{\pi a^2}{2}$

We need to calculate the emf

Using formula of emf

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{-\pi a^2B}{4}(-\omega\sin\omega t)$

$\epsilon=\dfrac{\pi a^2B\omega\sin(\omega t)}{4}$

We need to calculate the current

Using formula of current

$I(t)=\dfrac{\epsilon}{R}$

$I(t)=\dfrac{\dfrac{\pi a^2B\omega\sin(\omega t)}{4}}{R}$

$I(t)=\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$

Hence, The current induced in the loop is $\dfrac{\pi a^2 B\omega}{4R}\ \sin(\omega t)$ .

4 0

3 years ago

In certain martial arts, people practice breaking a piece of wood with the side of their bare hand. Use your understanding of im

VARVARA [1.3K]

There is so much force coming at once and adrenaline so you don't feel it

5 0

3 years ago

Read 2 more answers

Which two forces exist between the protons in an atom

r-ruslan [8.4K]

Answer: The Forces Between Protons at Nuclear Distances. Two protons are subject to two forces; the nuclear force and the electrostatic force. When they are very close together the nuclear force is dominant and when they are far apart it is the electrostatic force which is dominant.

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8 0

3 years ago

How would you get your friend to change his/her mind from using PED's?​

How would you get your friend to change his/her mind from using PED's?