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aivan3 [116]
3 years ago
7

which object would have more potential energy a bowling ball stored on a high shelf in a closet or a baseball on the same shelf?

why? which one would you rather fall on your head
Chemistry
1 answer:
AveGali [126]3 years ago
4 0

Explanation:

Potential energy mathematically is P = m×g×h.

Where m= mass of the ball, g= acceleration. due to gravity which is constant

and h= the height which is also same.

Since, a bowling ball has more mass than a baseball, therefore, its potential energy would be higher generally.

A baseball is more likely to fall on your head because of its round shape.

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Calculate the pH of a 0.30 M NaF solution. The Ka value for HF is 7.2*10^-4
Licemer1 [7]
We are given with the equilibrium constant of acid, HF and is asked to calculate the pH of 0.30 M NaF solution. The formula to be followed is 
Ka = [H+][F-]/[HF]Ka = 7.2 x 10 -4 = x^2/[0.3-x]x = [H+]= pH = -log (H+) = 1.84
5 0
3 years ago
What is the frequency of 3.98 x 10^-77 
LekaFEV [45]

Answer:

What is the frequency of a 6.9 x 10-13 m wave? 3.00 x 108 = 6.9x10-13 mly). GAMMA. V = 4.35 x 10 20 5-11. 3. What is the wavelength of a 2.99 Hz wave?

Missing: 3.98 ‎77 

Explanation:

5 0
3 years ago
What is the isotope notation of the element that has an atomic number of 24 and a mass number of 52?
Fofino [41]

Answer:

Chromium

Explanation:

Cr has 24 atomic number and mass number 52

4 0
2 years ago
What is a liquid mixture whose parts are evenly blended?.
Eva8 [605]

Answer:

A homogeneous mixture is a type of mixture in which the individual substances are evenly mixed.

Explanation:

3 0
2 years ago
a 125 g chunk of aluminum at 182 degrees Celsius was added to a bucket filled with 365 g of water at 22.0 degrees Celsius. Ignor
Diano4ka-milaya [45]
<h3>Answer:</h3>

32.98°C

<h3>Explanation:</h3>

We are given the following;

Mass of Aluminium as 125 g

Initial temperature of Aluminium as 182°C

Mass of water as 265 g

Initial temperature of water as 22°C

We are required to calculate the final temperature of the two compounds;

First, we need to know the specific heat capacity of each;

Specific heat capacity of Aluminium is 0.9 J/g°C

Specific heat capacity of water is 4.184 J/g°C

<h3>Step 1: Calculate the Quantity of heat gained by water.</h3>

Assuming the final temperature is X°C

we know, Q = mcΔT

Change in temperature, ΔT = (X-22)°C

therefore;

Q = 365 g × 4.184 J/g°C × (X-22)°C

    = (1527.16X-33,597.52) Joules

<h3>Step 2: Calculate the quantity of heat released by Aluminium </h3>

Using the final temperature, X°C

Change in temperature, ΔT = -(X°- 182°)C (negative because heat was lost)

Therefore;

Q = 125 g × 0.90 J/g°C × (182°-X°)C

  = (20,475- 112.5X) Joules

<h3>Step 3: Calculating the final temperature</h3>

We need to know that the heat released by aluminium is equal to heat absorbed by water.

Therefore;

(20,475- 112.5X) Joules = (1527.16X-33,597.52) Joules

Combining the like terms;

1639.66X = 54072.52

             X = 32.978°C

                = 32.98°C

Therefore, the final temperature of the two compounds will be 32.98°C

7 0
3 years ago
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