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sweet-ann [11.9K]
2 years ago
10

May you please rate my game out of ten, and also please telll me what I need to do to improve it, thx.

Engineering
2 answers:
Bingel [31]2 years ago
8 0
Yeah okay sure……:)!!!!!
stellarik [79]2 years ago
3 0

Hey hun^^

Your game was very fun. Here are a few bugs I found-

*At the beginning, the game flashed a few times before I could click start

*When I hit an obstacle the game froze and didn't take me back to the menu screen

*There are lots of obstacles. I suggest that you put levels and slowly make them easy to hard

Overall I rate this game an 8/10.

Great job!

~Alanna~

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Find the differential and evaluate for the given x and dx: y=sin2xx,x=π,dx=0.25
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By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

<h3>How to determine the differential of a one-variable function</h3>

Differentials represent the <em>instantaneous</em> change of a variable. As the given function has only one variable, the differential can be found by using <em>ordinary</em> derivatives. It follows:

dy = y'(x) · dx     (1)

If we know that y = (1/x) · sin 2x, x = π and dx = 0.25, then the differential to be evaluated is:

y' = -\frac{1}{x^{2}}\cdot \sin 2x + \frac{2}{x}\cdot \cos 2x

y' = \frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}}

dy = \left(\frac{2\cdot x \cdot \cos 2x - \sin 2x}{x^{2}} \right)\cdot dx

dy = \left(\frac{2\pi \cdot \cos 2\pi -\sin 2\pi}{\pi^{2}} \right)\cdot (0.25)

dy = \frac{1}{2\pi}

By applying the concepts of differential and derivative, the differential for y = (1/x) · sin 2x and evaluated at x = π and dx = 0.25 is equal to 1/2π.

To learn more on differentials: brainly.com/question/24062595

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Solution of the problem is given in the attachments.

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