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nordsb [41]
3 years ago
13

Question in the image

Chemistry
1 answer:
Sergeeva-Olga [200]3 years ago
3 0

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You might be interested in
3. Concentric circles (one smaller circle inside another). As
Agata [3.3K]

Answer:

Bohr's "planetary project" was widely accepted because he was able to explain a factor that Ruthford failed to achieve. Bohr was able to explain how electrons and energy worked in a simple atom, such as hydrogen, which consists of an electron orbiting a single proton.

In addition, he was able to explain, using the principles of gravity, how electrons do not fall on top of the proton but rather orbit around the proton.

Explanation:

Danish physicist Niels Bohr proposed an atomic model for the hydrogen atom which was later extended to other elements. Its model is based on the Solar System, in which the planets rotate around the sun. For Bohr, electrons rotate in orbit around the atomic nucleus grouped into energy levels.

Until 1913, there was no satisfactory model that explained even the simplest of atoms - hydrogen, which consists of an electron orbiting a single proton.

By assigning the concept of energy levels, Bohr was able to create a version of the hydrogen atom that was possibly stable and satisfying spectral observations. Until then, all theoretical predictions suggested that it should not exist for more than a split second - a failure that bothered physicists a great deal. It was therefore a monumental advance.

Bohr was also able to explain why electrons do not fall on protons using concepts of gravity. In Bohr's atomic model, electrons rotate around the nucleus like planets around the sun. According to Bohr, an electron does not fall into the nucleus because it cannot: its orbits are like steps in a ladder. We may be in one or the other but not in two. Imagine the atom as a kind of tiny football stadium.

The core is in the center of the lawn. Electrons can run around the steps of the stands. From time to time, they jump from step to step. If they go up they use energy, down they release energy.

However, electrons can never leave the stands to invade the field. Bohr did not explain why the ban.

8 0
4 years ago
The central atom in ________ does not violate the octet rule. the central atom in ________ does not violate the octet rule. sf4
ruslelena [56]

We have to know which do not violet octet rule.

The central atom in SF₄ does not violate the octet rule. the central atom in CF₄ does not violate the octet rule.

As per octet rule, atoms can combine either by transfer of valence electrons from one atom to another or by sharing of valence electrons in order to have an octet in their valence shell.

The central atom S of SF₄ contains 8 electrons in the valence shell. Also, C atom of CF₄ contains 8 electrons in the valence shell.

ICl₄⁻ contains 9 electrons in the outermost shell.

7 0
3 years ago
()
const2013 [10]

Answer:

\large \boxed{\text{-1276 kJ/mol}}

Explanation:

You calculate the energy required to break all the bonds in the reactants.

Then you subtract the energy needed to break all the bonds in the products.

                             CH₃CH₂OH        +  3O₂ ⟶ 2CO₂ + 3H₂O

Bonds:         5C-H 1C-C 1C-O 1O-H    3O=O     4C=O   6O-H

D/kJ·mol⁻¹:    413    347  358  467       495        799      467

\Delta H = \sum{D_{\text{reactants}}} - \sum{D_{\text{products}}}\\\sum{D_{\text{reactants}}} = 5 \times 413 + 1 \times 347 + 1 \times 358 + 1 \times 467 + 3 \times 495 = 3237 + 1485\\=\text{4722 kJ}\\\sum{D_{\text{products}}} = 4 \times 799 + 6 \times 467 =3196 + 2802 = \text{5998 kJ}\\\Delta H = 4722 - 5998= \textbf{-1276 kJ} \\ \text{The overall energy change is $\large \boxed{\textbf{-1276 kJ/mol}}$}.

6 0
4 years ago
When considering the relationship among standard free energy change, equilibrium constants, and standard cell potential, the equ
DedPeter [7]

Answer:

ΔG° = - RTLnK is used to find the standard cell  potential given the equilibrium constant

Explanation:

for an ideal disolution:

⇒ ΔG = RT∑ni LnXi

∴ ΔG = ( μi - μi*)ni

∴ μ : chemical potential

∴ μ*: chem. potential of the pure component at T and P.

⇒ ΔG = μi - μi* = RT LnXi

for a equilibrium reaction:

⇒ ∑ νi*μi = 0

⇒ ΔGr = ΔG°+ RT Ln Kx = 0

⇒ ΔG° = - RT LnKx

4 0
4 years ago
For each of the following species: C2+ & O2- Write the molecular orbital energy diagram and fill in the electrons Hint: in e
Tju [1.3M]

Molecular orbital energy is the energy associated with each electron in an atom or molecule.

It is expressed in electron volts (eV) and is determined by the electron's position in the atom or molecule. The molecular orbital energy diagram and fill-in the electrons are given here in each case, the number of valence electrons in the species is determined first; this is followed by the valence molecular orbital diagram for each species.

C2+: Molecular Orbital Energy Diagram

1s2 2s2 2p2

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 0 e-

π2p*  ← 0 e-  

π2p   ← 0 e-

Bond Order: 0

Stability: Unstable

Magnetism: Diamagnetic (no unpaired electrons)

O2-: Molecular Orbital Energy Diagram

1s2 2s2 2p4

σ2s*  ← 0 e-  

σ2s   ← 2 e-

σ2p*  ← 0 e-  

σ2p   ← 2 e-

π2p*  ← 0 e-  

π2p   ← 2 e-

Bond Order: 1

Stability: Stable

Magnetism: Paramagnetic (2 unpaired electrons)

For more questions like Molecular orbital theory click the link below:

brainly.com/question/20436223

#SPJ4

6 0
2 years ago
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