Answer:
A) v = 40 m / s, B) v_average = 20 m / s
Explanation:
For this exercise we will use the kinematics relations
A) the final velocity for t = 5 s and since the body starts from rest its initial velocity is zero
v = vo + a t
v = 0 + 8 5
v = 40 m / s
B) the average velocity can be found with the relation
v_average = vf + vo / 2
v-average = 0+ 40/2
v_average = 20 m / s
Answer:
The magnitude of the acceleration of the box is 2 m/s².
Explanation:
Given:
Mass of the box,
kg
Force acting towards east,
N
Frictional force acting towards west,
N
Let the acceleration be
m/s².
Now, net force acting on the box towards east is given as:

From Newton's second law of motion,

Therefore, the magnitude of the acceleration of the box is 2 m/s².
Marshmallow
When you it in water it float but the brick sinks
This is because marshmallow are sugar which is simple molecules combined by van set waals force
The brick is a giant ionic structure which adopts ionic bond the molecules are packed more closed
Answer:
The electron will get at about 0.388 cm (about 4 mm) from the negative plate before stopping.
Explanation:
Recall that the Electric field is constant inside the parallel plates, and therefore the acceleration the electron feels is constant everywhere inside the parallel plates, so we can examine its motion using kinematics of a constantly accelerated particle. This constant acceleration is (based on Newton's 2nd Law:

and since the electric field E in between parallel plates separated a distance d and under a potential difference
, is given by:

then :

We want to find when the particle reaches velocity zero via kinematics:

We replace this time (t) in the kinematic equation for the particle displacement:

Replacing the values with the information given, converting the distance d into meters (0.01 m), using
, and the electron's kinetic energy:

we get:
Therefore, since the electron was initially at 0.5 cm (0.005 m) from the negative plate, the closest it gets to this plate is:
0.005 - 0.00112 m = 0.00388 m [or 0.388 cm]