Answer:
Electric field due to uniformly charged sphere is 9.2 x 10⁴ N/C
Explanation:
Given :
Radius of the solid sphere, R = 42 cm = 0.42 m
Total charge on the sphere, Q = 23 μC = 23 x 10⁻⁶ C
Distance of the point from the center of the sphere, r = 150 cm = 1.5 m
Since, r > R, so the point is outside the sphere. Thus, the electric field outside the uniformly charged sphere is determine by the relation:

Here k is constant and its value is 9 x 10⁹ N·m²/C².
Substitute the suitable values in the above equation.

E = 9.2 x 10⁴ N/C
= t(Vf + Vi/2)
<span>Vf + Vi/2 = d/t </span>
<span>Vf = (d/t) - Vi/2 </span>
<span>Answer: Vf = (d/t) - Vi/2 OR (2dt - Vit)/2t
</span>
Answer:
45° to min.
1° ----> 60 min
45° ----> ?.
45 * 60
2700 min
<h3><u>2</u><u>7</u><u>0</u><u>0</u><u> </u><u>min</u></h3>
The gravitational pull will reduce, because the moon is moving further away from the centre of the earth. In other words, the further an object is from the centre of the earth, the weaker the gravitational pull that will be exerted on it.