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Sedbober [7]
3 years ago
7

Two people carry a heavy electric motor by placing it on a light board 2.45 m long. One person lifts at one end with a force of

410.0 N , and the other lifts at the opposite end with a force of 645.0 N . You may want to review (Page) . For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Playing on a seesaw. Part A What is the weight of the motor? Express your answer in newtons.

Physics
1 answer:
maxonik [38]3 years ago
5 0

Answer:

W=1055N

Explanation:

In order to solve this problem, we must first do a drawing of the situation so we can visualize theh problem better. (See attached picture)

In this problem, we will ignore the board's weight. As we can see in the free body diagram of the board, there are only three forces acting on the system and we can say the system is in vertical equilibrium, so from this we can say that:

\sum F=0

so we can do the sum now:

F_{1}+F_{2}-W=0

when solving for the Weight W, we get:

W=F_{1}+F_{2}

and now we can substitute the given data, so we get:

W=410N+645N

W=1055N

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A 64 kg swimmer jumps, with a velocity of 4.2 m/s, off the front of a 25 kg kayak when the kayak is moving forward at a velocity
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Answer:

3.88m/s

Explanation:

Using the law of conservation of momentum

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8 0
2 years ago
A short-wave radio antenna is supported by two guy wires, 155 ft and 175 ft long. Each wire is attached to the top of the antenn
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Answer:

163.8 ft

Explanation:

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Cos63 = \frac{BD}{AB} = \frac{BD}{155}\\BD = 155 Cos63 \\BD = 70.4 ft

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Using Pythagorean theorem in triangle ADC

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distance between the anchor points is given as

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