I don’t understand the question
        
             
        
        
        
A quantum (plural, quanta<span>) is the minimum amount of </span>energy<span> that can be absorbed or released by matter. It is a discrete, or distinct, amount of </span>energy<span>. ... Thus, they can occupy only fixed </span>energy levels<span> around the nucleus that correspond to quantum increases in </span>energy<span>.</span>
        
             
        
        
        
Answer:
ExplaAt high temperatures MgCO3 decomposes to magnesium oxide and carbon dioxide. This process is important in the production of magnesium oxide. This process is called calcining: MgCO3 → MgO + CO2 (ΔH = +118 kJ/mol)
nation:
 
        
             
        
        
        
Answer:
a) 0.11
b)76.9
c) 8.8
d) 1.7*10^-4
Explanation:
Step 1: Data given
K = 1.3 * 10^-2 for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g)
Step 2: Formula of K
aA(g) + bB(g) ⇌ cC(g) + dD(g) 
K = [C]^c *[D]^d  / [A]^a * [B]^b
K = 1.3 * 10^-2 = [NH3]² / [H2]³*[N2]
Step 3: 
a) 1/2N2 + 3/2H2(g) ⇌ NH3(g)
N2(g) + 3H2(g) ⇌ 2NH3
1/2N2 + 3/2H2(g) ⇌ NH3(g)    =>K' =  
K' =  = 0.11
 = 0.11
<em>b. 2NH3(g) ⇌ N2(g) + 3H2(g)</em>
N2(g) + 3H2(g) ⇌ 2NH3
2NH3(g) ⇌ N2(g) + 3H2(g)    =>K' = 1/K
K' = 1/(1.3*10^-2) = 76.9
c. NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)
N2(g) + 3H2(g) ⇌ 2NH3
NH3(g) ⇌ 1/2 N2(g) + 3/2H2(g)    
=>K' = 
K' = 
K' = 8.8
d. 2N2(g) + 6H2(g) ⇌ 4NH3(g)
N2(g) + 3H2(g) ⇌ 2NH3
2N2(g) + 6H2(g) ⇌ 4NH3(g) 
K' = K²
K' = (1.3*10^-2)²
K' = 1.7 *10 ^-4