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Alinara [238K]
3 years ago
14

If Lithium and Nitrogen created a bond what would the ratios be?

Chemistry
2 answers:
olga nikolaevna [1]3 years ago
5 0

Answer:

There would be three Lithium atoms per one Nitrogen atom.

3:1

Li3N (Lithium Nitride)

Explanation:

Group 15 elements usually have 5 valence electrons, and every atom wants to have a full valence shell of valence electrons. So, nitrogen can get three electrons from each Lithium atom in order to get a full octet.

dolphi86 [110]3 years ago
3 0
I think it’s 2.5 or 3 to 1
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A) 2Fe(s) + O2(g) =>
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Answer:  -22.2 kJ

Explanation:

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According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

(1)  2Fe(s)+O_2(g)\rightarrow 2FeO(s)  \Delta H_1=-544.0kJ

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(3)  Fe_3O_4(s)\rightarrow 3Fe(s)+2O_2(g)  \Delta H=+1118.4kJ

Reversing 1 ,2 and 3 and halving 1 and 2 and then adding we get net equation:

(4) Fe_2O_3(s)+FeO(s)\rightarrow Fe_3O_4(s)  \Delta H_4=?

\Delta H_4=\frac{-\Delta H_1}{2}+\frac{-\Delta H_2}{2}+(-\Delta H_3)=\frac{544.0}{2}+\frac{1648.4}{2}+(-1118.4)=-22.2kJ

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A double displacement reaction in which one of the product is formed as a solid is called as precipitation reaction.  

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