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stepladder [879]
3 years ago
7

Why is gunshot residue important for a forensic scientist? What are the potential complications with this type of evidence?

Chemistry
2 answers:
Jlenok [28]3 years ago
5 0

Answer 1: A gun shot residue is the powdery discharge that release after the firing process of the firearm. The powdery discharge consists of unburnt or partially burnt primer, propellants, fragments of the projectiles, cartilage cases  and residues present inside the firearm.

It is important for the forensic scientists so as to detect the culprit as these residues are left on the clothes and hands after firing. It can be used to identify the direction and distance of firing.

Answer 2: The complications associated with gunshot residue are:

1. The particles are very small and may exhibit low density they are likely to blow by wind so they may not be found at some crime scene.

2. As the powdery discharge consists of explosive particles in small amounts but on testing can explode and can cause harm.

erik [133]3 years ago
3 0
A residue from a gunshot is most likely gun powder, which tells you what kind of bullet was shot and the type of gun that was used to shoot the target/victim/person. Some complications may be that there is more than one gun or weapon which uses that residue, so it may be hard to pinpoint it and the bullet can't really tell you who it is unless there's DNA on the bullet, and the chemicals of the bullet may even destroy evidence.
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0.641 moles of ethane

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<em>Hess's law: ΔH products - ΔH reactants</em>

ΔH = {2ΔHCO2 + 3ΔHH2O} - {ΔHC2H6}

<em>Pure monoatomic substances have a ΔH = 0kJ/mol; ΔHO2 = 0kJ/mol</em>

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ΔH = {2*-393.5kJ/mol + 3*-285.8kJ/mol} - {-84.7kJ/mol}

ΔH = -1559.7kJ/mol

That means when 1 mole of ethane is in combustion there are released 1559.7kJ of heat. To produce 1.00x10³kJ there are needed:

1.00x10³kJ * (1mole ethane / 1559.7kJ) =

<h3>0.641 moles of ethane</h3>
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What is the empirical formula of a compound that breaks down into 4.12g of N and 0.88g of H? N 5 H NH 3 NH 4 N 4 H
Marysya12 [62]

<u>The </u><u>emperical formula </u><u>can be </u><u>calculated </u><u>as follows:</u>


<u>mass :</u>   4.12g of N            and        0.88g of H

<u>moles:</u>   4.12g/14.007       and        0.88g/1.008

               

<u>moles:</u>   0.294                   and        0.873


<u>moles/smallest number</u>:   (gives the ratio of atoms)


             0.294/0.294                and           0.873/0.294

                   1                               and             2.969

                    1                              and              3



The simplest ratio of N : H is 1 : 3

<u>Hence the </u><u>emperical formula </u><u>is </u><u>NH3</u>


<u>Explanation:</u>

 1.   The emperical formula can be found by getting  the <u>simplest ratio of atoms in a molecule.</u>

2. To get the simplest ratio of atoms we find out the <u>number of moles of each atoms in it.</u>

3. From the number of moles of atoms we can find the simplest ratio of each atom by dividing the <u>number of moles by the smallest number.</u>


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