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stepladder [879]
3 years ago
7

Why is gunshot residue important for a forensic scientist? What are the potential complications with this type of evidence?

Chemistry
2 answers:
Jlenok [28]3 years ago
5 0

Answer 1: A gun shot residue is the powdery discharge that release after the firing process of the firearm. The powdery discharge consists of unburnt or partially burnt primer, propellants, fragments of the projectiles, cartilage cases  and residues present inside the firearm.

It is important for the forensic scientists so as to detect the culprit as these residues are left on the clothes and hands after firing. It can be used to identify the direction and distance of firing.

Answer 2: The complications associated with gunshot residue are:

1. The particles are very small and may exhibit low density they are likely to blow by wind so they may not be found at some crime scene.

2. As the powdery discharge consists of explosive particles in small amounts but on testing can explode and can cause harm.

erik [133]3 years ago
3 0
A residue from a gunshot is most likely gun powder, which tells you what kind of bullet was shot and the type of gun that was used to shoot the target/victim/person. Some complications may be that there is more than one gun or weapon which uses that residue, so it may be hard to pinpoint it and the bullet can't really tell you who it is unless there's DNA on the bullet, and the chemicals of the bullet may even destroy evidence.
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How many grams of NaF should be added to 500 mL of a 0.100 M solution of HF to make a buffer with a pH of 3.2
Korolek [52]

Answer:

2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

The moles of HF are:

500mL = 0.500L * (0.100mol/L) = 0.0500 moles HF

Replacing:

3.2 = 3.17 + log [A-] / [0.0500moles]

0.03 = log [A-] / [0.0500moles]

1.017152 = [A-] / [0.0500moles]

[A-] = 0.0500mol * 1.017152

[A-] = 0.0536 moles NaF

The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
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Answer:

Energy in the campfire originates from the potential chemical energy of the wood, before it is burnt to warm and give light around the campfire.

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For a camp fire, the energy input is in the form of the potential chemical energy, stored up in the firewood used to fuel the flame.

The energy output is in the form of heat energy that the campfire radiates all around, light energy given off from the flame, and a little bit of sound energy, heard in the cracking of the firewood as they burn in the flame.

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Answer:

the standard cell potential value

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