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Makovka662 [10]
3 years ago
14

Why do scientist record observations during an experiment?

Chemistry
1 answer:
Sloan [31]3 years ago
3 0

Observation is more than simply noticing something. ... Observation is essential in science. Scientists use observation to collect and record data, which enables them to construct and then test hypotheses and theories.

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Which of the following equations represent
Harrizon [31]

Answer:

a. MgO(s) + H2CO3(aq) →  MgCO3(s) + H2O(l) DOUBLE DISPLACEMENT REACTION.

b. 2KNO3(s)→2KNO2 (s) + O2(8) DESCOMPOSITION REACTION.

c. H2(g) + CuO(s) → Cu(s) + H2O(1) SINGLE DISPLACEMENT REACTION.

d. NaOH(aq) + HCl(aq) →  NaCl(aq) + H2O(1) COMBUSTION  REACTION.

e. H2(8) + Cl2(g) → 2HCl(8) SYNTHESIS REACTION.

f. SO3(g) + H2O(1)→ H2SO4(aq) SYNTHESIS REACTION.

5 0
3 years ago
Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
Gre4nikov [31]
2.43 kilograms is equal to 2430 grams because 1 kilogram is equal to 1000 grams.
4 0
3 years ago
Read 2 more answers
When an acid or vase is added to to water,
velikii [3]

Answer:

yes

Explanation:

3 0
3 years ago
a sample of helium occupies a volume of 101.2 mL at a pressure of 790 mmHg. at what pressure would the volume be 120 mL?
AveGali [126]

Answer : The final pressure will be, 666.2 mmHg

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}

or,

P_1V_1=P_2V_2

where,

P_1 = initial pressure = 790 mmHg

P_2 = final pressure = ?

V_1 = initial volume = 101.2 mL

V_2 = final volume = 120 mL

Now put all the given values in the above equation, we get:

790mmHg\times 101.2mL=P_2\times 120mL

P_2=666.2mmHg

Therefore, the final pressure will be, 666.2 mmHg

6 0
3 years ago
The following thermochemical equation is for the reaction of Fe 3 O 4 (s) with hydrogen (g) to form iron and water vapor Fe 3 O
Mila [183]

Answer:

41.3kJ of heat is absorbed

Explanation:

Based in the reaction:

Fe₃O₄(s) + 4H₂(g) → 3Fe(s) + 4H₂O(g) ΔH = 151kJ

<em>1 mole of Fe3O4 reacts with 4 moles of H₂, 151kJ are absorbed.</em>

63.4g of Fe₃O₄ (Molar mass: 231.533g/mol) are:

63.4g Fe₃O₄ × (1mol / 231.533g) = <em>0.274moles of Fe₃O₄</em>

These are the moles of Fe₃O₄ that react. As 1 mole of Fe₃O₄ in reaction absorb 151kJ, 0.274moles absorb:

0.274moles of Fe₃O₄ × (151kJ / 1 mole Fe₃O₄) =

<h3>41.3kJ of heat is absorbed</h3>

<em />

6 0
3 years ago
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