Molar mass Li2CO3 = 73.89 g/mol
Molar mass Li = 6.94g/mol Li = 6.94*2 = 13.88g
% LI = 13.88/73.89*100 = 18.78% perfectly correct.
Answer:
506.912 L
Explanation:
From the question given above, the following data were obtained:
Number of mole of O₂ = 22.63 moles
Volume of O₂ =?
Recall:
1 mole of a gas occupy 22.4 L at STP.
With the above information, we obtained the volume occupied by 22.63 moles of O₂ as follow:
1 mole of O₂ occupied 22.4 L at STP.
Therefore, 22.63 moles of O₂ will occupy = 22.63 × 22.4 = 506.912 L at STP.
Thus, 22.63 moles of O₂ is equivalent to 506.912 L.
The correct answer is A. Charging by friction
Explanation
When someone rubs a comb with their hair when they are combing it and the hair sticks to the comb occurs a phenomenon called electrization, in which a neutral body becomes charged or loses an electrical charge (electrons). One way that electrization occurs is through the rubbing of two neutral bodies which causes one to be positively charged and the other negatively causing them to attract each other by magnetism. Therefore, the correct answer is A. Charging by friction
It is recommended only for the second type of candy to be taken off the market.
Based on the background information, if a candy shows a 0,62 Rf value in the chromatography it is considered potentially dangerous, and therefore it should be taken off the market.
The Rf value is calculated using the following formula:
- Rf = Total distance traveled by a component/ Total distance from the pencil line to the solvent front
Now, let's find out if any of the components has an Rf equal to 0,62.
Note: To determine the distances I measured the image using a ruler and you can do the same, this will not alter the results.
- Sample 1
- Total distance traveled by the component: 6cm
- Total distance: 7 cm
- Rf : 6 cm/ 7 cm = 0.85
2. Sample 2
- Total distance traveled by the component: 4.34cm
- Total distance: 7 cm
- Rf : 4.34 cm/ 7 cm = 0.62
This means sample 2 has the 0.62 Rf value and therefore it needs to be taken off the market.
Learn more about chromatography in: brainly.com/question/10296715
