B. The kinetic energy will decrease.
Answer:
<u>Sound barrier
:</u>
The sound barrier is defined as a <u><em>"barrier"</em></u> that travels in all directions (because we are talking about sound waves) at the typical speed of sound in the air (1235.5 km/h). It should be noted that the name of <u><em>"barrier"</em></u> was given because it was previously considered a physical limit that prevented large aircrafts from traveling at supersonic speed (a situation that was evident in fighter planes during World War II, having problems with compressibility when flying at high speeds). However, <u>today many planes are capable of overcoming that barrier without problems.
</u>
<u>
</u>
<u>When the Sound barrier is broken
:</u>
When an airplane approaches the speed of sound (defined in the upper lines), <u>it can be observed how the shape of the air that flows around it changes, because the wave fronts are grouping more and more.
</u>
Then, when the plane exceeds the speed of sound (the sound barrier), something known as sonic boom or sonic explosion occurs, which is nothing more than what our ears can hear when the shock wave caused by the plane exceeds the speed of sound.
It should be noted that this explosion can be annoying to the human ear.
The initial speed of the bullet = v₁= 511.07 m/s
<h3>Further explanation</h3>
Given
17.4 g bullet
5506 g wooden
The velocity of the block+bullet :1.61 m/s
Required
The initial speed
Solution
Momentum
m₁v₁+m₂v₂=m₁v₁'+m₂v₂'
v₂=0 ⇒block at rest
v₁'=v₂'=1.61 m/s
the equation becomes :
m₁v₁=(m₁+m₂)v'
17.4v₁=(17.4+5506)1.61
v₁= 511.07 m/s
Answer:
<h2>
a) Q = 0.759µC</h2><h2>
b) E = 39.5µJ</h2>
Explanation:
a) The charge Q on the positive charge capacitor can be gotten using the formula Q = CV
C = capacitance of the capacitor (in Farads )
V = voltage (in volts) = 100V
C = ∈A/d
∈ = permittivity of free space = 8.85 × 10^-12 F/m
A = cross sectional area = 600 cm²
d= distance between the plates = 0.7cm
C = 8.85 × 10^-12 * 600/0.7
C = 7.59*10^-9Farads
Q = 7.59*10^-9 * 100
Q = 7.59*10^-7Coulombs
Q = 0.759*10^-6C
Q = 0.759µC
b) Energy stored in a capacitor is expressed as E = 1/2CV²
E = 1/2 * 7.59*10^-9 * 100²
E = 0.0000395Joules
E = 39.5*10^-6Joules
E = 39.5µJ