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Gelneren [198K]
3 years ago
6

What is thermodynamics

Engineering
1 answer:
Alex17521 [72]3 years ago
4 0

Explanation:

Thermodynamics is the branch of science that deals with the relation between radiation, energy, physical properties of matter.

There are 4 laws of thermodynamics namely as follows :

Zeroth Law, First Law, Second Law and Third Law.

There are 4 branches of thermodynamics:

Classical thermodynamics, Statistical mechanics, Chemical thermodynamics and Equilibrium thermodynamics.

Hence, this is the required solution.

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A group of students launches a model rocket in the vertical direction. Based on tracking data, they determine that the altitude
Fofino [41]

Answer:

u = 260.22m/s

S_{max} = 1141.07ft

Explanation:

Given

S_0 = 89.6ft --- Initial altitude

S_{16.5} = 0ft -- Altitude after 16.5 seconds

a = -g = -32.2ft/s^2 --- Acceleration (It is negative because it is an upward movement i.e. against gravity)

Solving (a): Final Speed of the rocket

To do this, we make use of:

S = ut + \frac{1}{2}at^2

The final altitude after 16.5 seconds is represented as:

S_{16.5} = S_0 + ut + \frac{1}{2}at^2

Substitute the following values:

S_0 = 89.6ft       S_{16.5} = 0ft     a = -g = -32.2ft/s^2    and t = 16.5

So, we have:

0 = 89.6 + u * 16.5 - \frac{1}{2} * 32.2 * 16.5^2

0 = 89.6 + u * 16.5 - \frac{1}{2} * 8766.45

0 = 89.6 + 16.5u-  4383.225

Collect Like Terms

16.5u = -89.6 +4383.225

16.5u = 4293.625

Make u the subject

u = \frac{4293.625}{16.5}

u = 260.21969697

u = 260.22m/s

Solving (b): The maximum height attained

First, we calculate the time taken to attain the maximum height.

Using:

v=u  + at

At the maximum height:

v =0 --- The final velocity

u = 260.22m/s

a = -g = -32.2ft/s^2

So, we have:

0 = 260.22 - 32.2t

Collect Like Terms

32.2t = 260.22

Make t the subject

t = \frac{260.22}{ 32.2}

t = 8.08s

The maximum height is then calculated as:

S_{max} = S_0 + ut + \frac{1}{2}at^2

This gives:

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 32.2 * 8.08^2

S_{max} = 89.6 + 260.22 * 8.08 - \frac{1}{2} * 2102.22

S_{max} = 89.6 + 260.22 * 8.08 - 1051.11

S_{max} = 1141.0676

S_{max} = 1141.07ft

Hence, the maximum height is 1141.07ft

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3 years ago
The primary difference between integrated/concurrent engineering development and functional/sequential development is: Integrate
gogolik [260]

Answer:

Integrated development spends more money up front to order to save money in later stages.

Explanation:

The primary difference between integrated/concurrent engineering development and functional/sequential development is: Integrated development spends more money up front to order to save money in later stages.

Cost of integrated development is higher in the initial stages where setup has be made and proper training and education of employees are required and once it is done. It will save money in later stages.

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