In general, bury metal conduits at least 6 inches below the soil surface. You may also run them at a depth of 4 inches under a 4-inch concrete slab. Under your driveway, the conduits must be below a depth of 18 inches, and under a public road or alleyway, they must be buried below 24 inches.
The system includes a disk rotating on a frictionless axle and a bit of clay transferring towards it, as proven withinside the determine above.
<h3>What is the
angular momentum?</h3>
The angular momentum of the device earlier than and after the clay sticks can be the same.
Conservation of angular momentum the precept of conservation of angular momentum states that the whole angular momentum is usually conserved.
- Li = Lf where;
- li is the preliminary second of inertia
- If is the very last second of inertia
- wi is the preliminary angular velocity
- wf is the very last angular velocity
- Li is the preliminary angular momentum
- Lf is the very last angular momentum
Thus, the angular momentum of the device earlier than and after the clay sticks can be the same.
Read more about the frictionless :
brainly.com/question/13539944
#SPJ4
<h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>
Explanation:
<h2>Given:</h2>
m = 1,250 kg
= 30 km/hr
F = 1,700 N
t = 10 s
<h2>Required:</h2>
Final velocity
<h2>Equation:</h2><h3>Force</h3>
F = ma
where: F - force
m - mass
a - acceleration
<h3>Acceleration</h3>
a = 
where: a - acceleration
- initial velocity
- final velocity
t - time elapsed
<h2>Solution:</h2><h3>Solve for acceleration using the formula for force</h3>
F = ma
Substitute the value of F and m
(1700 N) = (1250 kg)(a)
a = 
a = 1.36 m/s²
<h3>Solve for final velocity using the formula for acceleration</h3>
= 
= 
- Substitute the value of a,
and t
a = 


= 
= 
<h2>Final answer</h2><h3><u>The velocity of the car after 10 s is 78.95 km/hr</u></h3>
Explanation:
Strengthening by grain size reduction
- It is based on the fact that dislocations will experience hindrances while trying to move from a grain into the next because of abrupt change in orientation of planes.
- Hindrances can be two types: forcible change of slip direction, and discontinuous slip plane.
- Smaller the grain size, often a dislocation encounters a hindrance. Yield strength of material will be increased.
- Yield strength is related to grain size (diameter, d ) as Hall Petch relation:

Strengthening by Grain size reduction (contd..)
- Grain size reduction improves not only strength, but also the toughness of many alloys.
- If d is average grain diameter,
is grain boundary area per unit volume,
is mean number of intercepts of grain boundaries per unit length of test line,
is number of grains per unit area on a polished surface:

- Grain size can also be measured by comparing the grains at a fixed magnification with standard grain size charts.
- Other method: Use of ASTM grain size number (Z). It is related to grain diameter, (in mm) as follows:

Solid solution strengthening
- Impure foreign atoms in a single phase material produces lattice strains which can anchor the dislocations.
- Effectiveness of this strengthening depends on two factors size difference and volume fraction of solute. Solute atoms interact with dislocations in many ways:
- elastic interaction
- modulus interaction
- stacking-fault interaction
- electrical interaction
- short-range order interaction
- long-range order interaction
Answer:
bypassed fraction B will be B= 0.105 (10.5%)
Explanation:
doing a mass balance of SO₂ at the exit
total mass outflow of SO₂ = remaining SO₂ from the scrubber outflow + bypass stream of SO₂
F*(1-er) = Fs*(1-es) + Fb
where
er= required efficiency
es= scrubber efficiency
Fs and Fb = total mass inflow of SO₂ to the scrubber and to the bypass respectively
F= total mass inflow of SO₂
and from a mass balance at the inlet
F= Fs+ Fb
therefore the bypassed fraction B=Fb/F is
F*(1-er) = Fs*(1-es) + Fb
1-er= (1-B)*(1-es) +B
1-er = 1-es - (1-es)*B + B
(es-er) = es*B
B= (es-er)/es = 1- er/es
replacing values
B= 1- er/es=1-0.85/0.95 = 2/19 = 0.105 (10.5%)