Answer:
44.95 tonnes
Explanation:
According to principle of buoyancy the object will just sink when it's weight is more than the weight of the liquid it displaces
It is given that empty weight of box = 40 tons
Let the mass of the stones to be placed be = M tonnes
Thus the combined mass of box and stones = (40+M) tonnes..........(i)
Since the box will displace water equal to it's volume V we have ![volume of box = 25ft*10ft*12ft= 3000ft^{3}](https://tex.z-dn.net/?f=volume%20of%20box%20%3D%2025ft%2A10ft%2A12ft%3D%203000ft%5E%7B3%7D)
![Since 1ft^{3} =0.028m^{3}](https://tex.z-dn.net/?f=Since%201ft%5E%7B3%7D%20%3D0.028m%5E%7B3%7D)
Now the weight of water displaced =
is density of water = 1000kg/![m^{3}](https://tex.z-dn.net/?f=m%5E%7B3%7D)
Thus weight of liquid displaced =
..................(ii)
Equating i and ii we get
40 + M = 84.95
thus Mass of stones = 44.95 tonnes
Answer:
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Explanation:
given data
pressure p1 = 1.4 MPa = 14 bar
temperature t1 = 32°C
exit pressure = 0.08 MPa = 0.8 bar
to find out
the quality of the refrigerant exiting the expansion valve
solution
we know here refrigerant undergoes at throtting process so
h1 = h2
so by table A 14 at p1 = 14 bar
t1 ≤ Tsat
so we use equation here that is
h1 = hf(t1) = 332.17 kJ/kg
this value we get from table A13
so as h1 = h2
h1 = h(f2) + x(2) * h(fg2)
so
exit quality = ![\frac{h1 - h(f2)}{h(fg2)}](https://tex.z-dn.net/?f=%5Cfrac%7Bh1%20-%20h%28f2%29%7D%7Bh%28fg2%29%7D)
exit quality = ![\frac{332.17- 9.04}{1382.73)}](https://tex.z-dn.net/?f=%5Cfrac%7B332.17-%209.04%7D%7B1382.73%29%7D)
so exit quality = 0.2337 = 23.37 %
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Answer:
Could ask a family member to help
Explanation: