Air expands through an ideal turbine from 1 MPa, 900 K to 0.1 MPa, 500K. The inlet velocity is small compared to the exit veloci
ty of 100 m/s. The turbine operates at steady state and develops a power output of 3,200 kW. Heat transfer between the turbine and its surroundings and any potential energy effects are negligible.
a. Calculate the mass flow rate of air, in kg/s, and the exit area, in m^2.
a. Calculate the mass flow rate of air, in kg/s, and the exit area, in m^2.
1 answer:
You might be interested in
Answer:
t = 6179.1 s = 102.9 min = 1.7 h
Explanation:
The energy provided by the resistance heater must be equal to the energy required to boil the water:
E = ΔQ
ηPt = mH
where.
η = efficiency = 84.5 % = 0.845
P = Power = 2.61 KW = 2610 W
t = time = ?
m = mass of water = 6.03 kg
H = Latent heat of vaporization of water = 2.26 x 10⁶ J/kg
Therefore,
(0.845)(2610 W)t = (6.03 kg)(2.26 x 10⁶ J/kg)
<u>t = 6179.1 s = 102.9 min = 1.7 h</u>