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klio [65]
3 years ago
13

PLEASE HELP!!

Mathematics
2 answers:
andrezito [222]3 years ago
8 0

Answer:

should be 96....I hope it's right

because volume is area of the base × the height × 1/3

Sveta_85 [38]3 years ago
8 0

Answer:

96

Step-by-step explanation:

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What fraction of 3/4 it will take to make 2/3
Marizza181 [45]
3/4x = 2/3

4/3(3/4)x = (2/3)(4/3)

x = 8/9
4 0
3 years ago
Which trigonometric function is being used if we get the fraction 6/10 as our answer? Question 3 options: sin(A) cos(A) tan(A) t
faust18 [17]

Answer:

cos A = 6/10

Step-by-step explanation:

That'd be cos A.  The cosine function is defined as the ratio

 adjacent side

------------------------

    hypotenuse

and here that ratio is cos A = 6/10.

3 0
4 years ago
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If matrix A is a 6 × 5 matrix, which order of matrix can be multiplied by matrix A?
Margaret [11]
It would be a 5 x 6 matrix 
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3 years ago
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How do I write 6 x 3/20 as a fraction in simplest form?
Talja [164]
First, you need to turn it into a fraction by doing the multiplication. 6/1 × 3/20 which is 18/20. then you simplify it to get 9/10. 9/10 is your answer
8 0
4 years ago
The dimensions of a rectangle are such that its length is 3 in. more than its width. If the length were doubled and if the width
Kay [80]

Answer:

The length of the rectangle is 11 inch and its width is 8 inch.

Step-by-step explanation:

Given:

Rectangle (R_1) and rectangle (R_2).

Let the width of the rectangle be 'x' inch.

Its length = '(x+3)' inch

Area of the rectangle = (A_1)

⇒A_1 = (x)(x+3)

Now for rectangle (R_2) its width is decreased by 1 inch and length is doubled,the area (A_2) will increased by 66 sq-inch.

So,

A_2=A_1+66

According to the question.

⇒ Area of rectangle (R_2)  with width '(x-1)' and length '2(x+3)'='(2x+6)' .

⇒ A_2=(x-1)(2x+6)

Plugging the values of A_2 in terms of A_1.

⇒ A_1+66= (x-1)(2x+6)

Plugging  A_1 = (x)(x+3) into the equation.

⇒ (x)(x+3)+66=(x-1)(2x+6)

⇒ x^2+3x+66=2x^2+6x-2x-6

⇒ x^2-2x^2+3x-6x+2x+6+66=0

⇒ -x^2-x+72=0

Now using quadratic formula we can find the value of 'x'.

Quadratic formula, (x)= \frac{\pm b+\sqrt{b^2-4ac} }{2a}

x= -9 and x= 8

Discarding the negative value.

Our width  = 'x' = 8 inches.

So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.

7 0
3 years ago
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