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mixas84 [53]
3 years ago
5

Pls help 7th grade science

Chemistry
2 answers:
aliya0001 [1]3 years ago
6 0

Answer:

It would be the first one, an overall positive charge on one end and overall negative charge on the other end.

Explanation:

Ket [755]3 years ago
5 0

Answer:

It's A.) A molecule that has an overall positive change in one end and an overall negative charge on the other

Explanation:

The definition of a polar molecule is a molecule with a negatively charged end and a positively charged end.

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If 9.5 atms of pressure were increased to 25 atms of pressure, what would be the final volume
nordsb [41]

Answer:

The final volume of the gas is 36.1 L.

Explanation:

Given:

Initial pressure of the gas is, P_1=9.5\ atm

Final pressure of the gas is, P_2=25\ atm

Initial volume of the gas is, V_1=95\ L

Final volume of the gas is, V_2=?

Here, we shall use Boyle's Law which states that for a process under constant temperature, the pressure of the gas changes inversely with the change in volume.

Here, the pressure is increased. So, the volume of the gas is decreased.

Therefore, as per Boyle's Law:

P_1V_1=P_2V_2\\9.5\times 95=25V_2\\902.5=25V_2\\V_2=\frac{902.5}{25}\\V_2=36.1\ L

So, the final volume of the gas is 36.1 L.

4 0
3 years ago
Which phrase defines altitude?
brilliants [131]
The height of a given point
4 0
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When 2 grams of powdered lead (IV) oxide was added to 100 cm3 of hydrogen peroxide, water and oxygen were produced. Lead (IV) ox
kirza4 [7]

Answer:

The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

Explanation:

Based on the given information this reaction is the catalytic decomposition of H₂O₂ into water and oxygen  using Lead (IV) oxide as a catalyst.

  1. The catalyst surface area is directly proportional to the reaction rate
  • So, Replacing the powdered lead oxide with its large crystals would decrease the reaction rate due to the has larger surface area than its large crystals.

     2. Also, Removing lead (IV) oxide from the reaction mixture  the reaction rate decreased because as the catalyst is removed.

     3.  Using 50 cm³ of hydrogen peroxide  doesn't affect the rate because the concentration of the reactant doesn't change.

     4. Using 1.0 gram of lead (IV) oxide would decrease the reaction rate because the amount of catalyst decreased

So, The right answer is:

Replacing the powdered lead oxide with its large crystals

Removing lead (IV) oxide from the reaction mixture

Using 1.0 gram of lead (IV) oxide

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The answer should be "Dunes"
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Where are blood cells produced? A. Red Cross B. Bones C. Digestive system D. Cirulatory system
wolverine [178]
B.Bones
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