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taurus [48]
3 years ago
4

A type of transmission line for electromagnetic waves consists of two parallel conducting plates (assumed infinite in width) sep

arated by a distance a. Each plate carries the same uniform surface current density of 16.0 A/m, but the currents run in opposite directions. What is the magnitude of the magnetic field between the plates at a point 1.00 mm from one of the plates if a = 0.800 cm? (μ0 = 4π × 10-7 T · m/A)
Physics
1 answer:
Elina [12.6K]3 years ago
7 0

Answer:

B=2.01 \times 10^{-5}\ T

Explanation:

Distance between plates = 0.8 cm

Distance from one plate = 1 mm

Current density (J)= 16 A/m

Currents are flowing in opposite direction.

\mu _o=4\pi \times 10^{-7}

When current is flowing in opposite direction then magnetic field given as

B=\dfrac{\mu _oJ}{2}+\dfrac{\mu _oJ}{2}

B=\mu _oJ

Now by putting the values we get

B=4\pi \times 10^{-7}\times 16

B=2.01 \times 10^{-5}\ T

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