Answer:
2L of water.
Explanation:
To know the volume of water to be added to the initial solution, first let us calculate the volume of the final solution. This is illustrated below:
Data obtained from the question:
Initial volume (V1) = 2L
Initial concentration (C1) = 6mol/L
Final concentration (C2) = 3mol/L
Final volume (V2) =?
Using the dilution formula, we can obtain the final volume of the stock as follow:
C1V1 =C2V2
6 x 2 = 3 x V2
Divide both side by 3
V2 = (6 x 2)/3
V2 = 4L.
The final volume of the solution is 4L.
To obtain the volume of water added, we shall determine the change in the volume of the solution. This is illustrated below:
Initial volume (V1) = 2L
Final volume (V2) = 4L
Change in volume = V2 – V1 = 4 – 2 = 2L.
Therefore, 2L of water must be added to the initial solution.
Answer:
the anwser is A just had it
Explanation:hope it helps
To calculate the number of molecules, we can simply use this rule:
number of molecules = number of moles x Avogadro's number
In this problem, we have:
number of moles = 4.56 moles
Avogadro's number is a constant = 6.02 x 10^23
Substituting in the above equation, we can calculate the number of molecules as follows:
number of molecules = 4.56 x 6.02 x 10^23
= 2.74512 x 10^24 molecules
Animals, plants, Humans
Hope this can help you!
