Question

One way of purifying gaseous H2 is to pass it under high pressure through the holes of a metal's crystal structure. Palladium, which adopts a cubic closest packed structure, absorbs more H2 than any other element and is one of the metals currently used for this purpose. Although the metal-hydrogen interaction is unclear, it is estimated that the density of absorbed H2 approaches that of liquid hydrogen (70.8 g/L). What volume (in L) of gaseous H2, measured at STP, can be packed into the spaces of 1 dm3 of palladium metal

Answer 1

Answer:

$V=795.26L$

Explanation:

From the question we are told that:

Volume $V=1dm^3=>1L$

Density $\rho=70.8g/L$

Generally the equation for Density is mathematically given by

$\rho =\frac{Mass}{Volume}$

Therefore

$M=\rho*V$

$M=70.8*1$

$M=70.8g$

Since at STP

$T=273K$

$P=1atm$

$Mass =70.8g$

Therefore

$Moles\ of\ Hydrogen=\frac{Mass}{2g}$

$Moles\ of\ Hydrogen=\frac{70.8}{2g}$

$Moles\ of\ Hydrogen=35.4moles$

Generally the equation for Ideal gas is mathematically given by

$PV=nRT$

Therefore

$V=\frac{nRT}{P}$

$V=\frac{35.4*0.0826*273}{1}$

$V=795.3L$