64158 calories is required
M=2.65kg=2650g
M=74g/mol
n = m/M = 2650g/74g/mol ≈ 35.81mol
Heat of fusion = 7.27kJ/mol
If 7.27kJ ------------- energy is in --------------- 1mol
than x ------------- energy is in --------------- 35.81mol
x = [35.81mol*7.27kJ]/1mol = <u>260.3387kJ</u>
Answer:
![C_{6} H_{6}](https://tex.z-dn.net/?f=C_%7B6%7D%20H_%7B6%7D)
Explanation:
First, find the mass of empirical formula, CH. 12.01 g/mol is for carbon, and 1.008 g/mol is for hydrogen. 12.01+1.008=13.018 G/mol CH. Divide 78.110 G/mol by 13.018 g/mol. You get approximately 6. Multiply that by the subscript of each element. 6(CH)=
![C_{6} H_{6}](https://tex.z-dn.net/?f=C_%7B6%7D%20H_%7B6%7D)
Answer:
2.73
Explanation:
2.72815277835894
i used an online converter lol it is much faster. if you'd like a step by step guide comment and ill give you one :)