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VashaNatasha [74]
3 years ago
11

Im not sure on this question can someone answer this?

Mathematics
2 answers:
saveliy_v [14]3 years ago
5 0

Answer:

[19+7÷(2×6)+1]

19+7÷12+1

26÷13

2

blagie [28]3 years ago
3 0

Answer:

Step-by-step explanation:

(19+7)÷(2×6+1)

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i dont know why i am in algebra when I dont understand it, is there anyone out there willing to help me understand it?
sp2606 [1]

Answer:

i belive the answer is  B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Bananas are $.59 a pound what is the constant of proportionality
hichkok12 [17]
The constant proportionality is the proportionality of 59. Because it is the price, you just move the decimal point two places over to the left.
If you do this correctly you will get .59
4 0
3 years ago
Rewrite each expression without using absolute value notation |7m-56| if m<8
dusya [7]

Considering the definition of the absolute value function, the expression is written as -7m + 56.

<h3>What is the definition of the absolute value function?</h3>

The absolute value function is defined as follows:

  • |x| = x, x \geq 0.
  • |x| = -x, x < 0

That is, where the expression is negative, it is multiplied by -1, while where it is not negative the expression is kept.

In this problem, the expression is:

|7m - 56|

For m < 8, we have that one example is m = 0:

7(0) - 56 = -56.

The expression is negative, hence the signal is changed, that is:

|7m - 56| = -(7m - 56) = -7m + 56.

More can be learned about the absolute value function at brainly.com/question/24734454

#SPJ1

7 0
2 years ago
Which of the following is an equivalent equation obtained by completing the square of the expression below? x^2+6x−8=0 A (x+3)^2
valentina_108 [34]

Answer:

Solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

Step-by-step explanation:

We need to solve the equation x^2+6x-8=0 by completing the square method.

For completing the square method: we need to follow: a^2+2ab+b^2=(a+b)^2

We are given:

x^2+6x-8=0

Solving by completing the square

x^2+2(x)(?)+(?)^2-8=0

We need to find ? in our case ? is 3 because 2*3= 6 and our middle term is 6x i,e 2(x)(3)=6x.

So, adding and subtracting (3)^2

x^2+2(x)(3)+(3)^2-8-(3)^2=0\\(x+3)^2-8-9=0\\(x+3)^2-17=0\\(x+3)^2=17

So, solving the equation x^2+6x-8=0 by completing the square method we get \mathbf{(x+3)^2=17}

Option B is correct option.

7 0
3 years ago
2/3x + 6 = 1/2x + 1/4x
Dmitriy789 [7]
2/3x + 6 = 1/2x + 1/4x ...multiply everything by 12
8x + 72 = 6x + 3x
8x + 72 = 9x
72 = 9x - 8x
72 = x
8 0
4 years ago
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