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madreJ [45]
3 years ago
14

Please HELP ASAP PLEASE I WILL MARK BRAINLIEST

Physics
1 answer:
Anika [276]3 years ago
3 0
It’s True the volume is 1k of iron is = 1
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15 to who helps me out!
s2008m [1.1K]

Answer:

a. same

b. less

c. same

d. same?

Explanation:

the mass will always be the same no matter where it is. the weight however depends on the gravity.

7 0
3 years ago
The speed of light is about 3.00 × 105 km/s. It takes approximately 1.28 seconds for light reflected from the
Ulleksa [173]
Just to correct you - the speed of light is 3.0 x 10^5 km/sec and not 105 km/sec as given by you (maybe it was just a typing mistake from your end).

The average distance between earth and moon would be - 384,000 kms. 

This is calculated by the formula -> Distance = Speed x Time.
 

8 0
3 years ago
Explain why radiation is dangerous for humans
Oksi-84 [34.3K]

Answer:

because it affects the attom in living things

7 0
2 years ago
Read 2 more answers
What happens when the fuel in a car engine combustion?​
Trava [24]

In a spark ignition engine, the fuel is mixed with air and then inducted into the cylinder during the intake process. After the piston compresses the fuel-air mixture, the spark ignites it, causing combustion. The expansion of the combustion gases pushes the piston during the power stroke.

Credit: Department of Energy

5 0
2 years ago
A car accelerates in the +x direction from rest with a constant acceleration of a1 = 1.76 m/s2 for t1 = 20 s. At that point the
alex41 [277]

Answer:

(a)v_1 = a_1t_1 = 1.76 t_1

(b) It won't hit

(c) 110 m

Explanation:

(a) the car velocity is the initial velocity (at rest so 0) plus product of acceleration and time t1

v_1 = v_0 + a_1t_1 = 0 +1.76t_1 = 1.76t_1

(b) The velocity of the car before the driver begins braking is

v_1 = 1.76*20 = 35.2m/s

The driver brakes hard and come to rest for t2 = 5s. This means the deceleration of the driver during braking process is

a_2 = \frac{\Delta v_2}{\Delta t_2} = \frac{v_2 - v_1}{t_2} = \frac{0 - 35.2}{5} = -7.04 m/s^2

We can use the following equation of motion to calculate how far the car has travel since braking to stop

s_2 = v_1t_2 + a_2t_2^2/2

s_2 = 35.2*5 - 7.04*5^2/2 = 88 m

Also the distance from start to where the driver starts braking is

s_1 = a_1t_1^2/2 = 1.76*20^2/2 = 352

So the total distance from rest to stop is 352 + 88 = 440 m < 550 m so the car won't hit the limb

(c) The distance from the limb to where the car stops is 550 - 440 = 110 m

8 0
3 years ago
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