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hoa [83]
2 years ago
9

Describe what happens to the system inside of a refrigerator or freezer in terms of heat transfer, work, and conservation of ene

rgy. Confine yourself to time periods in which the door is closed.
A. Work is done on the system and heat is transferred from the system for a net decrease in internal energy.
B. Work is done on the system and heat is transferred into the system for a net increase in internal energy.
C. Work is done by the system and heat is transferred into the system for a net decrease in internal energy.
D. Work is done by the system and heat is transferred from the system for a net decrease in internal energy.
Physics
1 answer:
Over [174]2 years ago
6 0

Answer: A. Work is done on the system and heat is transferred from the system for a net decrease in internal energy.

Explanation:

A refrigerator is a device which dispenses heat from the close system to a warmer area or in the surrounding. By dispensing the heat the internal temperature of the refrigerator drops. The system of refrigerator violates the second law of thermodynamics. As it performs the work to cool the region instead of heating the region. The work is done on the system and the internal energy decreases and the heat energy is liberated to the surrounding area. A refrigerator is an open system.

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Katyanochek1 [597]

1. 2 way radio

2. radio waves

3. communication

4. convert the voltage from a transmitter into a radio signal

5. signal strength refers to the transmitter power output

6. sorry, not so sure.. Though it might be the waves.

4 0
3 years ago
The kinetic energy of a rocket is increased by a factor of eight after its engines are fired, whereas its total mass is reduced
Rudik [331]

The momentum increases by a factor of 2

Explanation:

We can solve this problem by rewriting the momentum of the rocket in terms of the kinetic energy and the mass.

The kinetic energy of the rocket is:

K=\frac{1}{2}mv^2 (1)

where

m is the mass

v is the velocity

The momentum of the rocket is

p=mv (2)

From eq.(1) we get

v=\sqrt{\frac{2K}{m}}

and substituting into (2),

p=\sqrt{2mK}

Now in this problem we have:

- The kinetic energy of the rocket is increased by a factor 8:

K' = 8K

- The mass is reduced by half:

m'=\frac{m}{2}

Substituting, we find the new momentum:

p'=\sqrt{2(\frac{m}{2}(8K)}=\sqrt{4(2mK)}=2\sqrt{2mK}=2p

So, the momentum increases by a factor of 2.

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4 0
3 years ago
A mass of 2.50 kg is in a gravitational field of 14.0 N/kg. What force acts on the mass?
Olenka [21]
To determine the force that acts on the mass, just multiply the mass by the gravitational field. Using the given data,
                             F = (2.50 kg)(14 N/kg) = 35 N
Therefore, the force that acts on the mass is equal to 35 N. 
7 0
3 years ago
Read 2 more answers
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turn
inn [45]

Answer:

The answer to the question is

The ladybug begins to slide

Explanation:

To solve the question we assume that the frictional force of the ladybug and the gentleman bug are the same

Where the  frictional force equals F_{Friction} = μ×N = m×g×μ

and the centripetal force is given by m·ω²·r

If we denote the properties of the ladybug as 1 and that of the gentleman bug as 2, we have

m₁×g×μ = m₁·ω²·r₁ ⇒ g×μ = ω²·r₁

and for the gentleman bug we have

m₂×g×μ = m₂·ω²·r₂ ⇒ g×μ = ω²·r₂

But r₁ = 2×r₂

Therefore substituting the values of r₁ =2×r₂ we have

g×μ = ω²·r₁ = g×μ = ω²·2·r₂

Therefore   ω²·r₂ = 0.5×g×μ for the ladybug. That is the ladybug has to overcome half the frictional force experienced by the gentleman bug before it start to slide

The ladybug begins to slide

6 0
3 years ago
9.
mote1985 [20]

Answer:

D. location

Explanation:

The gravitational field strength of Earth is determined by the virtue of the location within the Earth's gravitational field.

That's why all objects regardless of their mass, shape, and size free fall towards the Earth with an acceleration equal to the acceleration at that location in the absence of air resistance.

According to the gravitational force between two bodies, the force experienced by one body due to the other is independent of its own mass.

The gravitational force is given by equation

                                  F =  GMm/r²

If F is the force acting on the smaller body of mass 'm', then

                                 F = ma

Therefore, the equation becomes,

                                ma = GMm/r²

                                   a = GM/r²

The value of 'a' changes with respect to the value of 'r' such that if 'r' is the radius of the Earth, then the acceleration at a height 'h' from Earth surface is given by

                                 a = GM/(r+h)²

Here it is clear that the acceleration at any point is only the inherent property of the Earth itself.

The gravitational field strength of Earth is determined by the virtue of the location within the Earth's gravitational field.

6 0
3 years ago
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