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Fudgin [204]
3 years ago
7

can any body tell me what is the relation in between halogen group and van der wals foce of attraction.why it increase down the

group in periodic table?
Chemistry
2 answers:
SashulF [63]3 years ago
6 0
Van der waal force α area of contact.

The above mathematical relation suggests that greater the contact area, greater is the van der waal force. 

As we move down the halogen group, area of contact between the molecule increses and hence van der waal forces also increases.

Hope this cleared your doubt, feel free to ask questions and have a nice day/night ahead! :)
Volgvan3 years ago
5 0
Because the size of atoms increase as you move down the periodic table.
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In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account
hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0
3 years ago
"which is a correct description of the organization of subatomic particles in atoms?"
Irina18 [472]
Which is a correct description of the organization of subatomic particles in atoms?

Protons and neutrons are tightly packed into a small nucleus. Electrons occupy the space
outside the nucleus

hope this helps.
5 0
3 years ago
Calculate the partial pressure of each gas and the total pressure if the temperature of the gas is 15 ∘C.
umka2103 [35]

Answer:

P(oxygen gas) = 3.75atm

P(helium) = 19.2atm

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Explanation:

8 0
3 years ago
Distinguish between a solution in general and an aqueous solution
Sveta_85 [38]

Answer:

  • What distinguish a solution in general from an aqueous solution is the solvent. A solution in general may contain any solvent, which may be solid, liquid or gas, while an aqueous solution is formed with water as solvent.

Explanation:

A solution in general is a homogeneous mixture in which a substance, named solute, is dissolved, in other substance, name solvent.

Solutions may be in solid, liquid or gas state. There are many kind of solvents. Usually, in a lab you work with liquid solutions. Some liquid solvents are: ethanol, glycerin, hexane, benzene, and water, among many others.

Aqueous solution is a solution where the solvent is water. Of course, the solute may be any one: NaCl, sugar, ethanol, an acid, a base, a salt.

What distinguish a solution in general and an aqueous solution is the solvent.

3 0
3 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
3 years ago
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