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miss Akunina [59]
3 years ago
8

Quentin is playing baseball and is batting. He swings and hits the ball sending it flying to the outfield. Which is greater- the

force of the ball on the bat or the force of the bat on the ball ?
Physics
1 answer:
Bess [88]3 years ago
5 0

Answer:

The force of the ball on the bat is same as the force of the bat on the ball.  

Explanation:

A bat hits the ball and the ball moves to the out filed.

According to the Newton's third law, for every action there is an equal and opposite reaction.

The action and the reaction forces acts on the two different bodies but the magnitude of the force is same.  

As the ball is hitted by the bat, the bat exerts the force on the ball and the same force is exerted on the bat by the ball according to the Newton's third law.

So, the force of the ball on the bat is same as the force of the bat on the ball but the direction of force is opposite.  

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Define what is boyleâs law?
lawyer [7]

Answer:

Volume of given mass of gas is inversely proportional to pressure of gas

Explanation:

Boyle's law: It states that the volume of given mass of gas is inversely proportional  to the pressure of gas at constant temperature.

Mathematical representation:

Suppose, a gas of mass m

T=Constant temperature

V=Volume of gas

P=Pressure of gas

Then, V\propto\frac{1}{P}

8 0
4 years ago
Electrons are continuously being knocked out of air molecules by cosmic ray particles from space. Once the electrons are free, t
nata0808 [166]

(a) 1.25\cdot 10^{-14} J

The change in potential energy of the electron is given by:

\Delta U=q E d

where

q=1.6\cdot 10^{-19}C is the magnitude of the electron's charge

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta U=(1.6\cdot 10^{-19}C)(150 N/C)(520 m)=1.25\cdot 10^{-14} J

(b) 78 kV

The potential difference the electron has moved through is given by

\Delta V=Ed

where

E=150 N/C is the magnitude of the electric field

d = 520 m is the distance through which the electron has moved

Substituting into the equation, we find

\Delta V=Ed=(150 N/C)(520 m)=78,000 V=78 kV

4 0
3 years ago
A remote-controlled car's wheel accelerates at 22.6 rad/s2 . If the wheel begins with an angular speed of 10.2 rad/s, what is th
Lapatulllka [165]

Answer:

70.9pi rad/s

Explanation:

angle turned through = 16

angular acceleration = 22.6 rad/s2

angular speed = 10.2 rad/s

time = ?

angular acceleration = angular speed/time

time = 10.2/22.6

time = <u>0</u><u>.</u><u>4</u><u>5</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u>

<u>angular speed</u><u> </u><u>=</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>t</u><u>u</u><u>r</u><u>n</u><u>e</u><u>d</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u>/</u><u>t</u><u>i</u><u>m</u><u>e</u>

<u>angular speed</u><u> </u><u>=</u> (16 × 2pi)/0.45

= 70.9pi rad/s

3 0
3 years ago
Mutations are always harmful. <br> true or false
masha68 [24]

Answer:

false

Explanation:

some can be harmful but not all

5 0
3 years ago
Read 2 more answers
A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b
Artist 52 [7]

<u>Answer:</u>

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

    Distance traveled during time t = 4 cm

    Initial velocity = u m/s

   Acceleration = 0 m/s^2

So 4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}

Now at time 2t,

  S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm

  So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

  Distance traveled during time t = 4 cm

    Initial velocity = 0 m/s

   Acceleration = -g m/s^2

4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}

At time 2t,

     S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm

 So vertical distance traveled in time 2t = 16 cm to the bottom

 

6 0
3 years ago
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