Hey there!
pH = - log [ H⁺ ] = 3.52
[ H⁺ ] = 10^-pH
[ H⁺] = 10^ ( -3.52 )
[H⁺] = 3.02*10⁻⁴ M
[HA] =0.175 M
Therefore:
Ka = [ H⁺]* [A⁻] / [ HA]
Ka = (3.02*10⁻⁴)² / 0.175
Ka = 9.1204*10⁻⁸ / 0.175
Ka = 5.2*10⁻⁷
Hope that helps!
valence of magnesium is 2
and valence of sulfate-ion is 2 too
answer: MgSO4•7H2O
There are approximately 4 resonance structures that can be drawn for N205 (no N-N bond) (minimal formal charge).
Answer:
Yes it would
Explanation: Well it kinda depend on the voltage and how the battery has been in use or based on the condition
The answer is "opposite charges."
