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2 years ago

What is the frequency of a wave that has a wavelength of 0.78 m and a speed

Physics

2 answers:

Cerrena [4.2K]2 years ago

4 0

Answer:

C. f = 440 Hz

Explanation:

In any wave, there is a fixed relationship between the wavelength (distance between two sucesive crests), the frequency (number of cycles per unit time) and the perturbation speed, as follows:

$v = \lambda * f (1)$

where v = speed of the wave

λ = wavelength

f = frequency

Replacing by the givens in (1) and solving for f, we have:

$f = \frac{343 m/s}{0.78m} = 440 Hz$

f = 440 Hz

Arada [10]2 years ago

3 0

Answer:

440 Hz

Explanation:

just is

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HOPE THIS HELPS YOU MATE!!
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2 years ago

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Mercury has a radial acceleration of 3.96 × 10−2 m/s2 and its orbital period is T = 88 days. What is the radius of Mercury’s orb

Maslowich

Answer: 58,045,522,878.8 meters

Explanation:

Ok, the data we have is

Period = T = 88 days

Radial acceleration = ar = 3.96x10^-2 m/s^2

And we know that the equation for the radial acceleration is:

ar = v^2/r = r*w^2

Where v is the velocity. r is the radius and w is the angular velocity.

And we know that:

w = 2*pi*f

where f is the frequency, and:

T = 1/f.

Then we can write:

w = 2*pi/T

and our equation becomes:

ar = r*(2*pi/T)^2

Now we solve this for r.

First we need to use the same units in both equations, so we want to write T in seconds.

T = 88 days,

A day has 24 hours, and one hour has 3600 seconds:

T = 88*24*3600 s =7,603,200s

Then:

3.96x10^-2 m/s^2 = r*(2*3.14/7,603,200s)^2

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3 years ago