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andrezito [222]
3 years ago
14

Find the volume of the prism.

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0

Answer:

102

Step-by-step explanation:

first you have to multiply 8 by 12 and then add the some with the leftover number

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What is the area of the enlarged trapezoid?
ludmilkaskok [199]
1.5 but I could be wrong I would double check
6 0
3 years ago
How do I solve for X?
elena-s [515]
The distance from the external point ^2 = The external segment of the secant * the full length of the secant.
tangent distance = 6
External portion of the secant = 3
Full length of the secant = x + 3

6^2 = 3*(x + 3) Remove the brackets. 
36 = 3x + 9  Subtract 9 from both sides.
36 - 9 = 3x
27 = 3x Divide by 3
x = 9  <<<<<<<Answer.
7 0
3 years ago
Evaluate : <br> \(\cos 12 \cos 24 \cos 36 \cos 48 \cos 72 \cos 84\)
NeTakaya
The answer in itself is 1/128 and here is the procedure to prove it:
cos(A)*cos(60+A)*cos(60-A) = cos(A)*(cos²60 - sin²A) 

<span>= cos(A)*{(1/4) - 1 + cos²A} = cos(A)*(cos²A - 3/4) </span>

<span>= (1/4){4cos^3(A) - 3cos(A)} = (1/4)*cos(3A) </span>

Now we group applying what we see above

<span>cos(12)*cos(48)*cos(72) = </span>
<span>=cos(12)*cos(60-12)*cos(60+12) = (1/4)cos(36) </span>

<span>Similarly, cos(24)*cos(36)*cos(84) = (1/4)cos(72) </span>

<span>Now the given expression is: </span>

<span>= (1/4)cos(36)*(1/4)*cos(72)*cos(60) = </span>

<span>= (1/16)*(1/2)*{(√5 + 1)/4}*{(√5 - 1)/4} [cos(60) = 1/2; </span>
<span>cos(36) = (√5 + 1)/4 and cos(72) = cos(90-18) = </span>
<span>= sin(18) = (√5 - 1)/4] </span>
<span>And we seimplify it and it goes: (1/512)*(5-1) = 1/128</span>
4 0
3 years ago
a chef made two batches of soup. While making the first batch, he added 1/8 teaspoon of salt, tasted it, and then added another
barxatty [35]

Answer:

20 teaspoons

Per batch amounts:

Salt = 15/3 = 5 teaspoons

garlic powder = 6/3 = 2 teaspoons

8 teaspoons of garlic powder number of batches:

8/2 = 4 batches

4 batches of salt

4 * 5 = 20 teaspoons

Step-by-step explanation:

Hope this helps:) Also hi lofi girl nice to meet you lol

7 0
3 years ago
Find the interquartile range for a data set having the five-number summary: 3.4, 10.8, 16.7, 23.1, 31.5
natita [175]

.Answer:

D. 12.3

Step-by-step explanation:

Arrange the data in increasing order

3.4, 10.8, 16.7, 23.1, 31.5

⇒This is an odd set of numbers, to find the interquartile range you include the median in both quartiles.

Locate the median/center value

3.4, 10.8, 16.7, 23.1, 31.5

Find lower half and find the median

lower half values⇒3.4, 10.8, 16.7

Median=Q1=10.8

Find the upper half and find

upper half= 16.7,23.1, 31.5

median= 16.7,23.1,31.5

Q3=23.1

Interquartile range=Q3-Q1

23.1-10.8=12.3

5 0
3 years ago
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