A box of highlighters originally cost

What is the total surface area of the object shown below including visible and non visible sides

Olenka [21]

Answer:

scan it plz its really easy if you scan them

8 0

3 years ago

I’ll give someone brainliest if they answer this

Dimas [21]

Answer:

2. The answer should be the last one.

3. The answer should be the first three.

Step-by-step explanation:

Question 2

KE = (1/2)mv²

2KE = mv²

v² = 2KE/m

v = ±√(2KE/m)

Therefore the answer should be the last one.

Question 3

b^(1/2) * b^(5/2)

Remember that the product rule states that b^x * b^y = b^(x+y)

So this means b^(1/2) * b^(5/2) = b^(1/2+5/2) = b^(6/2) = b^3

Also remember that the power rule states that √b = b^(1/2)

so this means b^(6/2) can also be written as (√b)^6

Therefore the answer should be the first three.

If you want to double check all of your answers, just replace b with a number (for example, 2), and plug all of the choices into the calculator. Just make sure you are very careful when typing into the calculator.

3 0

2 years ago

Question 15 (5 points)

VARVARA [1.3K]

Answer: $230

Step-by-step explanation:

Since the discount Eric got was 75% of the normal price, you would divide 172.50 by 0.75 and you would end up getting the original price, or $230.

7 0

3 years ago

Read 2 more answers

Alex buys 24 apples and when he opens it 6 apples are bad whats the perecentage of the bad apples

nataly862011 [7]

6/24=1/4=25%

answer is 25% are bad

6 0

3 years ago

Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 4.6 parts

kirill115 [55]

Answer:

$z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666$

$p_v =2*P(Z$

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.

Step-by-step explanation:

Data given and notation

$\bar X=4.5$ represent the sample mean

$\sigma=1.1$ represent the population standard deviation

$n=860$ sample size

$\mu_o =4.6$ represent the value that we want to test

$\alpha=0.02$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is equal or not to 4.6, the system of hypothesis would be:

Null hypothesis: $\mu = 4.6$

Alternative hypothesis: $\mu \neq 4.6$

If we analyze the size for the sample is > 30 and we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{4.5-4.6}{\frac{1.1}{\sqrt{860}}}=-2.666$

P-value

Since is a two sided test the p value would be:

$p_v =2*P(Z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.02$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 4.6 at 2% of signficance.

5 0

3 years ago