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bixtya [17]
3 years ago
11

A car travelling at 40 m/s comes to a halt in 8 seconds. What is the car’s acceleration and how far does it travel while it is s

topping?
Physics
1 answer:
IrinaVladis [17]3 years ago
7 0

Answer: Acceleration = 5m/s^2; Distance traveled = 320 m

Explanation:

Velocity of car = 40m/s

Time taken = 8 seconds

Acceleration = ?

Distance traveled = ?

A) Since acceleration is the rate of change of velocity per unit time

i.e acceleration = velocity / time

acceleration = 40m/s / 8 seconds

Acceleration = 5m/s^2

B) To get how far the car traveled before stopping, obtain the distance from the formula:

velocity = distance traveled / time

40m/s = distance / 8 seconds

Distance = 40m/s x 8 seconds

Distance = 320 m

Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.

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3 0
2 years ago
What will be the final temperature if a 4.00 g silver ring at 41.0◦C if it gives off 18.0 J of heat to the surroundings? The spe
Eduardwww [97]

Answer:

Final temperature, T_f=21.85^{\circ}

Explanation:

Given that,

Mass of silver ring, m = 4 g

Initial temperature, T_i=41^{\circ}C

Heat released, Q = -18 J (as heat is released)

Specific heat capacity of silver, c=0.235\ J/g\ C

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Final temperature

Solution,

The expression for the specific heat is given by :

Q=mc\Delta T

Q=mc(T_f-T_i)

T_f=\dfrac{-Q}{mc}+T_i

T_f=\dfrac{-18}{4\times 0.235}+41

T_f=21.85^{\circ}

So, the final temperature of silver is 21.85 degrees Celsius.

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