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bixtya [17]
3 years ago
11

A car travelling at 40 m/s comes to a halt in 8 seconds. What is the car’s acceleration and how far does it travel while it is s

topping?
Physics
1 answer:
IrinaVladis [17]3 years ago
7 0

Answer: Acceleration = 5m/s^2; Distance traveled = 320 m

Explanation:

Velocity of car = 40m/s

Time taken = 8 seconds

Acceleration = ?

Distance traveled = ?

A) Since acceleration is the rate of change of velocity per unit time

i.e acceleration = velocity / time

acceleration = 40m/s / 8 seconds

Acceleration = 5m/s^2

B) To get how far the car traveled before stopping, obtain the distance from the formula:

velocity = distance traveled / time

40m/s = distance / 8 seconds

Distance = 40m/s x 8 seconds

Distance = 320 m

Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.

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Answer:

B = 7.9012*10^{-5}T

Explanation:

To solve the problem, the concepts related to the magnetic field and the current produced in a lightning bolt are necessary.

The current is defined by the load due to time, that is to say

I= \frac{q}{t}

Where,

q= Charge

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So the current can be expressed as:

I = \frac{16}{1.5*10^{-3}}

I = 10666.67A

Once the current is found it is now possible to find the magnetic field, as this is given by the equation,

B =\frac{\mu_0}{2\pi}\frac{I}{r}

Where,

\mu_0 =Permeability Constant

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Replacing the values we have

B=\frac{4\pi*10^{-7}}{2\pi}(\frac{10666.67}{27})

B = 7.9012*10^{-5}T

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3 years ago
Which of the following statements cannot be supported by Kepler's laws of planetary motion? a. The distance of a planet around t
hodyreva [135]

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A weightlifter lifts a 250-kg mass 0.5 meters above his head, how much PEg does the mass have (Note: g=9.8 m/s2)? Round your ans
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Answer:

1225 J

Explanation:

The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by

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where

m is the mass

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h is the height at which the object has been lifted

In this problem, we have

m = 250 kg

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So, the PE of the object is

PE=(250 kg)(9.8 m/s^2)(0.5 m)=1225 J

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Sound waves produced by a source pass a point five times every second. Which of the following choices correctly describes the pe
Ugo [173]

The period is 1/5 second, and the frequency is 5 Hz.

Explanation:

Let's start by reviewing some definitions about waves:

- The period of a wave is the time taken for the wave to make one complete cycle. It is indicated with T and it is measured in seconds (s)

- The frequency of a wave is the number of complete cycles made by the wave in one second. It is indicated with f and it is measured in Hertz (Hz). It is equal to the reciprocal of the period:

f=\frac{1}{T}

where f is the frequency and T is the period.

In this problem, we have a wave that passes a given point five time per second. This means that the number of oscillations per second is five, and so its frequency is:

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It follows than the period of the wave is:

T=\frac{1}{f}=\frac{1}{5}s

Therefore, the correct statement is

The period is 1/5 second, and the frequency is 5 Hz.

Learn more about waves, frequency and period:

brainly.com/question/5354733

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#LearnwithBrainly

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