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bixtya [17]
3 years ago
11

A car travelling at 40 m/s comes to a halt in 8 seconds. What is the car’s acceleration and how far does it travel while it is s

topping?
Physics
1 answer:
IrinaVladis [17]3 years ago
7 0

Answer: Acceleration = 5m/s^2; Distance traveled = 320 m

Explanation:

Velocity of car = 40m/s

Time taken = 8 seconds

Acceleration = ?

Distance traveled = ?

A) Since acceleration is the rate of change of velocity per unit time

i.e acceleration = velocity / time

acceleration = 40m/s / 8 seconds

Acceleration = 5m/s^2

B) To get how far the car traveled before stopping, obtain the distance from the formula:

velocity = distance traveled / time

40m/s = distance / 8 seconds

Distance = 40m/s x 8 seconds

Distance = 320 m

Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.

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An object of the same mass has three different weights at different times.
Sindrei [870]

Answer:

See below

Explanation:

Possible.....mass is the amount of matter an object has ....weight is the result of gravity on an object.... different gravity ( Earth , Moon or Mars etc)

results in different weights .

5 0
1 year ago
The space shuttle releases a satellite into a circular orbit 630 km above the Earth.
solniwko [45]

Answer:

7,539 m/s

Explanation:

Let's use this equation to find the gravitational acceleration of this space shuttle:

  • \displaystyle g=\frac{GM}{r^2}

We know that G is the gravitational constant: 6.67 * 10^(-11) Nm²/kg².

M is the mass of the planet, which is Earth in this case: 5.972 * 10^24 kg.

r is the distance from the center of Earth to the space shuttle: radius of Earth (6.3781 * 10^6 m) + distance above the Earth (630 km → 630,000 m).

Plug these values into the equation:

  • \displaystyle g=\frac{(6.67\cdot 10^-^1^1 \ Nm^2kg^-^2)(5.972\cdot 10^2^4 \ kg)}{[(6.3781\cdot 10^6 \ m)+(630000 \ m)]^2}

Remove units to make the equation easier to read.

  • \displaystyle g=\frac{(6.67\cdot 10^-^1^1 )(5.972\cdot 10^2^4 )}{[(6.3781\cdot 10^6)+(630000 )]^2}

Multiply the numerator out.

  • \displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(6.3781\cdot 10^6)+(630000 )]^2}

Add the terms in the denominator.

  • \displaystyle g=\frac{(3.983324\cdot 10^1^4)}{[(7008100)]^2}

Simplify this equation.

  • \displaystyle g=8.11045189 \ \frac{m}{s^2}

The acceleration due to gravity g = 8.11045189 m/s². Now we use the equation for acceleration for an object in circular motion which contains v and r.

  • \displaystyle a = \frac{v^2}{r}

a = g, v is the velocity that the space shuttle should be moving (what we are trying to solve for), and r is the radius we had in the previous equation when solving for g.

Plug these values into the equation and solve for v.

  • \displaystyle 8.11045189 \ \frac{m}{s^2}  = \frac{v^2}{7008100 \ m}  

Remove units to make the equation easier to read.

  • \displaystyle 8.11045189   = \frac{v^2}{7008100}

Multiply both sides by 7,008,100.

  • 56838857.89=v^2

Take the square root of both sides.

  • v=7539.154985

The shuttle should be moving at a velocity of about 7,539 m/s when it is released into the circular orbit above Earth.

5 0
2 years ago
Which is an example of a chemical change?
yulyashka [42]
It’s burning wax. All of the other options are physical changes .
3 0
3 years ago
The hardest known natural material is _____. <br> jade<br> quartz<br> diamond<br> talc
kakasveta [241]
Its diamond i am 100% right!

8 0
3 years ago
Read 2 more answers
A baseball is thrown horizontally at a rate of 40m/s toward a home plate 18.4 m away. How far below the launch height is the bal
sammy [17]

Answer:

<h3>1.03684m</h3>

Explanation:

Using the formula for calculating range expressed as;

R = U√2H/g where

R is the distance moves in horizontal direction = 18.4m

H is the height

U is the velocity of the baseball = 40m/s

g is the acceleration due to gravity = 9.8m/s²

Substitute the given parameters into the formula and calculate H as shown;

18.4 = 40√2H/9.8

18.4/40 = √2H/9.8

0.46 = √2H/9.8

square both sides;

(0.46)² = (√2H/9.8)²

0.2116 = 2H/9.8

2H = 9.8*0.2116

2H = 2.07368

H = 2.07368/2

H = 1.03684m

Hence the ball is 1.03684m below the launch height when it reached home plate.

8 0
2 years ago
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