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bixtya [17]
3 years ago
11

A car travelling at 40 m/s comes to a halt in 8 seconds. What is the car’s acceleration and how far does it travel while it is s

topping?
Physics
1 answer:
IrinaVladis [17]3 years ago
7 0

Answer: Acceleration = 5m/s^2; Distance traveled = 320 m

Explanation:

Velocity of car = 40m/s

Time taken = 8 seconds

Acceleration = ?

Distance traveled = ?

A) Since acceleration is the rate of change of velocity per unit time

i.e acceleration = velocity / time

acceleration = 40m/s / 8 seconds

Acceleration = 5m/s^2

B) To get how far the car traveled before stopping, obtain the distance from the formula:

velocity = distance traveled / time

40m/s = distance / 8 seconds

Distance = 40m/s x 8 seconds

Distance = 320 m

Thus, the car’s acceleration is 5m/s^2 while it traveled 320 metres before stopping.

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Multiply 5.036×102m by 0.078×10−1, taking into account significant figures.
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Answer : The significant digit is 6

Explanation :

Multiply 5.036\times10^{2}m by 0.078\times10^{-1}m

Now, on multiplying

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.392808 \times10^{1}\ m^{2}

5.036\times10^{2}m \times0.078\times10^{-1}m = 0.0392808\ m^{2}

Now, the significant digit is 6.

Hence, this is the required solution.

3 0
3 years ago
Vygotsky’s theory of cognitive development states that an individual constructs knowledge primarily through interaction with imp
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Answer:

false

Explanation:

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Describe the basic particle from which all elements are made
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3 years ago
6. 15. A boy takes 5 seconds to reach each point from ‘A’ to ‘B’, ‘B’ to ‘C’ and ‘C’ to ‘D’ as
Dafna1 [17]

Explanation:

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3 0
3 years ago
We would like to place an object 45.0cm in front of a lens and have its image appear on a screen 90.0cm behind the lens. What mu
liubo4ka [24]

Answer:

the radii of curvature is 30 cm.

Explanation:

given,

object is place at = 45 cm

image appears at = 90 cm

focal length = ?

refractive index = 1.5

radii of curvature = ?

\dfrac{1}{f} = \dfrac{1}{u} +\dfrac{1}{v}

\dfrac{1}{f} = \dfrac{1}{45} +\dfrac{1}{90}

f = 30 cm

using lens formula

\dfrac{1}{f} = (n-1)(\dfrac{1}{R_1} -\dfrac{1}{R_2})

R_1 = R\ and\ R_2 = -R

\dfrac{1}{f} = (n-1)(\dfrac{1}{R} +\dfrac{1}{R})

R = (n -1)\ f

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3 years ago
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