Answer:
The maximum induced emf is 15.08 V
Explanation:
Given;
number of turns of the generator, N = 6 turns
area of the loop, A = 0.04 m
magnetic field of the loop, B = 0.2 T
frequency of loop, f = 50 Hz
The maximum induced emf is given by;
E = NBAω
Where;
ω is the angular speed = 2πf
E = NBA(2πf)
E = 6 x 0.2 x 0.04 x (2 x 3.142 x 50)
E = 15.08 V
Therefore, the maximum induced emf is 15.08 V
To calculate the horizontal velocity component, use the cosine identity. where cos A = a / h
where A is the angle the golfer hits the ball
a is the horizontal component velocity
h is the speed the golfer hits the ball
so a = h cos A
a = 31 cos 35
a = 25.4 m/s
Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m
Answer: Interneurons.
These interneurons transmit impulses to other neurons and thus form a part of the reflux arc.
