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3 years ago

What force will a proton experience in a uniform electric field whose strength is 2.00 x 10^5 Newtons per Coulomb? *

Physics

1 answer:

Alenkasestr [34]3 years ago

7 0

Answer: F =3.218 * 10^-11 N

Explanation: The relationship between electric field intensity and force is given by

F = Eq.

F= Force on electron

E = strength of electric field = 2*10^5

q= magnitude of proton charge = 1.609 * 10^-19c

F = 2* 10^5 * 1 609 * 10^-16

F = 3.218 * 10^-11 N

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A body is traveling at 5.0 m/s along the positive direction of an x axis; no net force acts on the body. An internal explosion s

loris [4]

To solve this problem it is necessary to apply the concepts related to the conservation of momentum and conservation of kinetic energy.

By definition kinetic energy is defined as

$KE = \frac{1}{2} mv^2$

Where,

m = Mass

v = Velocity

On the other hand we have the conservation of the moment, which for this case would be defined as

$m*V_i = m_1V_1+m_2V_2$

Here,

m = Total mass (8Kg at this case)

$m_1=m_2 =$ Mass each part

$V_i =$ Initial velocity

$V_2 =$ Final velocity particle 2

$V_1 =$ Final velocity particle 1

The initial kinetic energy would be given by,

$KE_i=\frac{1}{2}mv^2$

$KE_i = \frac{1}{2}8*5^2$

$KE_i = 100J$

In the end the energy increased 100J, that is,

$KE_f = KE_i KE_{increased}$

$KE_f = 100+100 = 200J$

By conservation of the moment then,

$m*V_i = m_1V_1+m_2V_2$

Replacing we have,

$(8)*5 = 4*V_1+4*V_2$

$40 = 4(V_1+V_2)$

$V_1+V_2 = 10$

$V_2 = 10-V_1$ (1)

In the final point the cinematic energy of EACH particle would be given by

$KE_f = \frac{1}{2}mv^2$

$KE_f = \frac{1}{2}4*(V_1^2+V_2^2)$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$ (2)

So we have a system of 2x2 equations

$V_2 = 10-V_1$

$200J=\frac{1}{2}4*(V_1^2+V_2^2)$

Replacing (1) in (2) and solving we have to,

200J=\frac{1}{2}4*(V_1^2+(10-V_1)^2)

PART A: $V_1 = 10m/s$

Then replacing in (1) we have that

PART B: $V_2 = 0m/s$

8 0

3 years ago

If a man weighs 750 n on the earth, what would he weigh on jupiter, where the free-fall acceleration is 25.9 m/s2?

Zepler [3.9K]

1982.14N is the answer

4 0

4 years ago

Electricity from the local power company costs 5.79 cents/kWh. How much would it cost to run a 120-W stereo system for 4.0 hours

xenn [34]

Answer:

Answer: B. $0.78.

Explanation:

Cost of Electricity

The rate of the cost of electricity is usually expressed in $/kWh or cents/kWh because the consumption of electricity is measured in Kilowatts-hour.

The local power company charges 5.79 cents/kWh.

We are required to calculate the cost to run a 120 W stereo system for 4 hours per day for 4 weeks.

The total consumption time is 4 hours/day * 7 days/week *4 weeks = 112 hours

The total energy consumed is 120 W * 112 h =13,440 Wh.

Converting to kWh: 13,440 Wh/1,000 = 13.440 kWh.

Finally, we multiply by the cost rate: 5.79 cents/kWh * 13.440 kWh = 77.8 cents/100 = $0.78.

Answer: B. $0.78.

3 0

3 years ago

A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of

Dafna1 [17]

Answer:

- pendulum use to determine acceleration

Explanation:

by calculating need to understand first the problem

the length is measure to be 2s

the lenght is also 2

2 obtainer on invistigation the most nearly is 8.

5 0

3 years ago

An element from group 2 on the periodic table will bond lonically with elements from group 17(7A)

Natalija [7]

Answer:

Elements in group IIA have 2 electrons in their outermost shell so they can donate these electrons of group VII A which have seven electrons in their outermost shell. So it is necessary 2 elements of group VII A, each atoms accepts one electron.

Explanation:

8 0

3 years ago