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irga5000 [103]
2 years ago
12

What force will a proton experience in a uniform electric field whose strength is 2.00 x 10^5 Newtons per Coulomb? *

Physics
1 answer:
Alenkasestr [34]2 years ago
7 0

Answer: F =3.218 * 10^-11 N

Explanation: The relationship between electric field intensity and force is given by

F = Eq.

F= Force on electron

E = strength of electric field = 2*10^5

q= magnitude of proton charge = 1.609 * 10^-19c

F = 2* 10^5 * 1 609 * 10^-16

F = 3.218 * 10^-11 N

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Read 2 more answers
3.Three resistors of 25.0Ω, 30.0Ω, and 40.0Ω are in a series circuit with a 6.0-volt battery. What is the current in the circuit
AURORKA [14]

Answer:

Current = 0.063 Amperes

Explanation:

Let the three resistors be R1, R2, and R3 respectively.

Given the following data;

R1 = 25.0Ω,

R2 = 30.0Ω

R3 = 40.0Ω

Voltage = 6 Volts

First of all, we would determine the equivalent or total resistance;

Total resistance (in series) = R1 + R2 + R3

Total resistance = 25.0Ω + 30.0Ω + 40.0Ω

Total resistance = 95 Ω

Next, we find the current flowing through the circuit;

Voltage = current * resistance

Substituting into the formula, we have;

6 = current * 95

Current = 6/95

Current = 0.063 Amperes

5 0
3 years ago
1. A brick and a peanut are dropped of the roof of a house at the same time, which
iris [78.8K]

Answer:

It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give

Explanation:

3 0
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