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irga5000 [103]
3 years ago
12

What force will a proton experience in a uniform electric field whose strength is 2.00 x 10^5 Newtons per Coulomb? *

Physics
1 answer:
Alenkasestr [34]3 years ago
7 0

Answer: F =3.218 * 10^-11 N

Explanation: The relationship between electric field intensity and force is given by

F = Eq.

F= Force on electron

E = strength of electric field = 2*10^5

q= magnitude of proton charge = 1.609 * 10^-19c

F = 2* 10^5 * 1 609 * 10^-16

F = 3.218 * 10^-11 N

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A 55.0-g piece of copper wire is heated, and the temperature of the wire changes from 19.0°C to 86.0°C. The amount of heat absor
Alinara [238K]
The specific heat of a metal or any element or compound can be determined using the formula Cp = delta H / delta T / mass. delta pertains to change. That is change in enthalpy and change in temperature. From the given data, Cp is equal to 343 cal per (86-19) c per 55 grams. This is equal to 0.093 cal / g deg. Celsius
4 0
3 years ago
If you put 120 volts of electricity through a pickle, the pickle will smoke and start glowing orange-yellow. The light is emitte
Alona [7]

Answer:

2.11eV

Explanation:

We know that speed of light is it's wavelength times frequency.

\therefore f=v/\lambda\\=(3\times10^8m/s)/(589mm\times1m/1\times 10^9nm)\\=5.09\times10^1^4s^-1 \ or \ 5.09\times10^1^4Hz

Planck's constant is 6.626\times 10^3^4Js

The energy gap is calculated by multyplying the light's frequency by planck's constant:

E_c=5.09\times10^1^4s^-^1\times 6.626\times10^-^3^4Js\\\\=3.37\times 10^-^1^9J  \ \ \ \ \ \ #1eV=1.06\times 10^-^1^9J\\\\=2.11eV

Hence, the energy gap is 2.11eV

4 0
3 years ago
A wave's frequency is 2Hz and its wavelength is 4 m. What is the wave's speed?
icang [17]

Wave speed = (wavelength) x (frequency)

                       =      (4 m)        x  (2 /sec)

                       =               8 m/sec

7 0
3 years ago
An archer defending a castle is on an 15.5 m high wall. He shoots an arrow straight down at 22.8 m/s. How much time does it take
kodGreya [7K]

Answer:

  about 602 milliseconds

Explanation:

The motion can be approximated by the equation ...

  y = -4.9t^2 -22.8t +15.5

where t is the time since the arrow was released, and y is the distance above the ground.

When y=0, the arrow has hit the ground.

Using the quadratic formula, we find ...

  t = (-(-22.8) ± √((-22.8)^2 -4(-4.9)(15.5)))/(2(-4.9))

  = (22.8 ± √823.64)/(-9.8)

The positive solution is ...

  t ≈ 0.60195193

It takes about 602 milliseconds for the arrow to reach the ground.

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3 years ago
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