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3 years ago

6

A force does work on an object if a component of the force:a. is perpendicular to the displacement of the object b. is parallel

to the displacement of the objectc. is crossing the line of axis d. both a and b are correct

1 answer:

MAVERICK [17]3 years ago

8 0

As we know that total work done by a force is given by

$W = F.d$

$W = Fdcos\theta$

so it is product of force and displacement along same direction

as we can write it as

$W = (Fcos\theta)(d)$

so it must be the product of force and displacement in same directions so correct answer must be

<u>b. is parallel to the displacement of the object</u>

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sdas [7]

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Explanation:

Given

length of wire $l=75\ cm$

change in length $\Delta l=1.85\ mm$

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$\Delta l=\dfrac{Pl}{AE}$

Where A=area of cross-section

$A=\dfrac{Pl}{\Delta lE}$

$A=\dfrac{98\times 0.75}{1.85\times 10^{-3}\times 7.9\times 10^{10}}$

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also wire is the shape of cylinder so cross-section is given by

$A=\dfrac{\pi d^2}{4}=5.029\times 10^{-7}\ m^2$

$\Rightarrow d^2=\dfrac{5.029\times 10^{-7}\times 4}{\pi }$

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